Maven:读取 属性 文件并复制资源

Maven: Read property file and copy resources

我遇到了一些场景,即读取属性文件,并根据 属性 文件的值创建文件夹并将资源从某个目录复制到它。

properties-file: xyz.properties

CLIENTLIST=A,B

我想在 maven 中执行以下步骤。

1. From above properties file pom should read the property.
2. In loop I want to create folders by name A and B. 
3. After creating folder i want to copy some resources into it.
  ex: after creating folder A , want to copy some resource files from x/y/z directory.

maven 可以吗?

我使用了几个插件来做到这一点,

<plugins>
 <plugin>
   <groupId>org.codehaus.mojo</groupId>
   <artifactId>properties-maven-plugin</artifactId>
   <version>1.0.0</version>
   <executions>
   <execution>
   <id>read property file</id>
   <phase>install</phase>
   <goals>
     <goal>read-project-properties</goal>
   </goals>
   <configuration>
     <files>
        <file>${basedir}/dirOne/xyz.properties</file>
     </files>
   </configuration>
   </execution>
   </executions>
</plugin>

<plugin>
  <groupId>com.soebes.maven.plugins</groupId>
  <artifactId>iterator-maven-plugin</artifactId>
  <version>0.3</version>
  <executions>
   <execution>
    <phase>install</phase>
    <goals>
      <goal>iterator</goal>
     </goals>
     <configuration>
       <content>${CLIENTLIST}</content>
       <pluginExecutors>
       <pluginExecutor>
       <plugin>
 <artifactId>maven-resources-plugin</artifactId>
 <version>2.6</version>
 </plugin>
 <goal>copy-resources</goal>
 <configuration>
    <outputDirectory>${basedir}/dirTwo/@item@/</outputDirectory>
    <resources>
    <resource>
      <directory>${basedir}/src/main/resources/</directory>
      <includes>
        <include>**/*.xml</include>
        <include>**/*.properties</include>
      </includes>
      <excludes><exclude>**/*.cmd</exclude></excludes>
    </resource>
    </resources>
  </configuration>
  </pluginExecutor>
  </pluginExecutors>
  </configuration>
  </execution>
  </executions>
  </plugin>
  </plugins>
</build>

我已经使用属性读取、迭代器和复制资源插件来获得我需要的东西。

  1. 首先我阅读了 属性 文件。
  2. 在循环中迭代从属性文件中读取的值。
  3. 并循环创建文件夹并将资源复制到创建的文件夹。