将 reducer 分配给嵌套状态 属性?
Assign reducer to nested state property?
使用下面的 react/redux 设置:
index.js
import React from 'react';
import { render } from 'react-dom';
import { Provider } from 'react-redux';
import App from './components/app';
import configureStore from './store';
let initialState = {
foods: {
apple: {
selected: false,
flavors: {
sweet: true,
salty: false
}
},
potatoChips: {
selected: false,
flavors: {
sweet: false,
salty: true
}
}
},
drinks: {
< some other object >
}
}
let store = configureStore(initialState);
render(
<Provider store={store}>
<App/>
</Provider>,
document.getElementById('app')
)
store.js
import { applyMiddleware, compose, createStore } from 'redux';
import rootReducer from './root-reducer';
import logger from 'redux-logger';
import thunk from 'redux-thunk';
let finalCreateStore = compose(
applyMiddleware(thunk, logger())
)(createStore)
let defInitialState = < same object as initialState above >
export default function configureStore(initialState = defInitialState){
return finalCreateStore(rootReducer, initialState)
}
root-reducer.js
import { combineReducers } from 'redux';
import appleReducer from './apple-reducer';
import potatoChipsReducer from './potato-chips-reducer';
const rootReducer = combineReducers({
foods.apple: appleReducer,
foods['potatoChips']: potatoChipsReducer
// HOW DO I DO THE ABOVE ASSIGNMENT?
})
export default rootReducer
我可以像上面 root-reducer.js
中尝试的那样为 state.foods.apple
分配一个减速器吗?或者我应该以不同的方式解决这个问题?
extratextsothisquestionisntallcodeandcanbesubmitted
可以嵌套combineReducers
.
示例:https://jsfiddle.net/2rhs2m9y/
const foodsReducer = combineReducers({
apple: appleReducer,
potatoChips: potatoChipsReducer,
})
const rootReducer = combineReducers({
foods: foodsReducer,
})
因此您的 appleReducer
将仅接收 foods.apple
树作为其状态,依此类推。
您也可以这样做(这实际上是 combineReducers
为您所做的):
const rootReducer = combineReducers({
foods: (state, action) => ({
apple: appleReducer(state.apple, action),
potatoChips: potatoChipsReducer(state.potatoChips, action),
}),
})
使用下面的 react/redux 设置:
index.js
import React from 'react';
import { render } from 'react-dom';
import { Provider } from 'react-redux';
import App from './components/app';
import configureStore from './store';
let initialState = {
foods: {
apple: {
selected: false,
flavors: {
sweet: true,
salty: false
}
},
potatoChips: {
selected: false,
flavors: {
sweet: false,
salty: true
}
}
},
drinks: {
< some other object >
}
}
let store = configureStore(initialState);
render(
<Provider store={store}>
<App/>
</Provider>,
document.getElementById('app')
)
store.js
import { applyMiddleware, compose, createStore } from 'redux';
import rootReducer from './root-reducer';
import logger from 'redux-logger';
import thunk from 'redux-thunk';
let finalCreateStore = compose(
applyMiddleware(thunk, logger())
)(createStore)
let defInitialState = < same object as initialState above >
export default function configureStore(initialState = defInitialState){
return finalCreateStore(rootReducer, initialState)
}
root-reducer.js
import { combineReducers } from 'redux';
import appleReducer from './apple-reducer';
import potatoChipsReducer from './potato-chips-reducer';
const rootReducer = combineReducers({
foods.apple: appleReducer,
foods['potatoChips']: potatoChipsReducer
// HOW DO I DO THE ABOVE ASSIGNMENT?
})
export default rootReducer
我可以像上面 root-reducer.js
中尝试的那样为 state.foods.apple
分配一个减速器吗?或者我应该以不同的方式解决这个问题?
extratextsothisquestionisntallcodeandcanbesubmitted
可以嵌套combineReducers
.
示例:https://jsfiddle.net/2rhs2m9y/
const foodsReducer = combineReducers({
apple: appleReducer,
potatoChips: potatoChipsReducer,
})
const rootReducer = combineReducers({
foods: foodsReducer,
})
因此您的 appleReducer
将仅接收 foods.apple
树作为其状态,依此类推。
您也可以这样做(这实际上是 combineReducers
为您所做的):
const rootReducer = combineReducers({
foods: (state, action) => ({
apple: appleReducer(state.apple, action),
potatoChips: potatoChipsReducer(state.potatoChips, action),
}),
})