Python:将元组转换为逗号分隔的字符串
Python: Convert tuple to comma separated String
import MySQLdb
db = MySQLdb.connect("localhost","root","password","database")
cursor = db.cursor()
cursor.execute("SELECT id FROM some_table")
u_data = cursor.fetchall()
>>> print u_data
((1320088L,),)
我在网上找到的东西让我走到了这里:
string = ((1320088L,),)
string = ','.join(map(str, string))
>>> print string
(1320088L,)
我期望的输出结果:
#Single element expected result
1320088L
#comma separated list if more than 2 elements, below is an example
1320088L,1320089L
我认为 string
是 tuple
的 tuple
包含长值。
>>> string = ((1320088L,),)
>>> ','.join(str(y) for x in string for y in x if len(x) > 0)
'1320088'
>>>
例如有多个值
>>> string = ((1320088L,1232121L),(1320088L,),)
>>> ','.join(str(y) for x in string for y in x if len(x) > 0)
'1320088,1232121,1320088'
>>>
首先使用 itertools.chain_fromiterable()
展平您的嵌套元组,然后 map()
进行字符串化和 join()
。请注意,str()
删除了 L
后缀,因为数据不再是 long
.
类型
>>> from itertools import chain
>>> s = ((1320088L,),)
>>> ','.join(map(str,chain.from_iterable(s)))
'1320088'
>>> s = ((1320088L,1232121L),(1320088L,),)
>>> ','.join(map(str,chain.from_iterable(s)))
'1320088,1232121,1320088'
注意,string
不是一个好的变量名,因为它与 string
模块相同。
string = ((1320088L,),)
print(','.join(map(str, list(sum(string, ())))))
string = ((1320088L, 1232121L), (1320088L,),)
print(','.join(map(str, list(sum(string, ())))))
输出:
1320088
1320088,1232121,1320088
import MySQLdb
db = MySQLdb.connect("localhost","root","password","database")
cursor = db.cursor()
cursor.execute("SELECT id FROM some_table")
u_data = cursor.fetchall()
>>> print u_data
((1320088L,),)
我在网上找到的东西让我走到了这里:
string = ((1320088L,),)
string = ','.join(map(str, string))
>>> print string
(1320088L,)
我期望的输出结果:
#Single element expected result
1320088L
#comma separated list if more than 2 elements, below is an example
1320088L,1320089L
我认为 string
是 tuple
的 tuple
包含长值。
>>> string = ((1320088L,),)
>>> ','.join(str(y) for x in string for y in x if len(x) > 0)
'1320088'
>>>
例如有多个值
>>> string = ((1320088L,1232121L),(1320088L,),)
>>> ','.join(str(y) for x in string for y in x if len(x) > 0)
'1320088,1232121,1320088'
>>>
首先使用 itertools.chain_fromiterable()
展平您的嵌套元组,然后 map()
进行字符串化和 join()
。请注意,str()
删除了 L
后缀,因为数据不再是 long
.
>>> from itertools import chain
>>> s = ((1320088L,),)
>>> ','.join(map(str,chain.from_iterable(s)))
'1320088'
>>> s = ((1320088L,1232121L),(1320088L,),)
>>> ','.join(map(str,chain.from_iterable(s)))
'1320088,1232121,1320088'
注意,string
不是一个好的变量名,因为它与 string
模块相同。
string = ((1320088L,),)
print(','.join(map(str, list(sum(string, ())))))
string = ((1320088L, 1232121L), (1320088L,),)
print(','.join(map(str, list(sum(string, ())))))
输出:
1320088
1320088,1232121,1320088