使用 awk 添加列值

Question

使用 awk 添加列：

x,y,8,0,0,0,0,0,0,0  
m,z,0,0,0,0,0,0,0,0  
a,b,206,1,0,2,0,0,0,0  
c,d,211,0,0,0,0,0,0,1  
e,f,8,0,0,1,0,0,0,0  
g,h,5,0,0,0,0,0,0,0  
i,j,2,0,0,0,0,0,0,0  
k,l,36,0,0,0,0,0,0,0  
m,n,2,0,0,0,0,0,0,0  
o,p,43,0,0,1,0,0,0,0  
q,r,2153,28,1,5,0,0,5,3  
s,t,96,0,0,0,0,0,0,0  
u,v,25,0,0,0,0,0,0,0  
x,y,4,0,0,0,0,0,0,0  
,,2799,29,1,9,0,0,5,4  

awk -F, '{for (i=1;i<=NR;i++) sum[i]+=$i;}; END{for (i in sum) print sum[i];}' file1

但它正在换行打印。

Answer 1

你能试试这个吗;

这是对行求和并插入每行的最后。

 awk -F, '{sum=0; for (i=1; i<=NF; i++) { sum+= $i } print [=10=] "," sum}' file1

要对列求和，

awk 'BEGIN{FS=OFS=","} {for (i=1;i<=NF;i++) sum[i]+=$i} END{for(i=1;i<=NF;i++) printf sum[i] OFS; printf "\n"}' file1

测试：

$ awk 'BEGIN{FS=OFS=","} {for (i=1;i<=NF;i++) sum[i]+=$i} END{for(i=1;i<=NF;i++) printf sum[i] OFS; printf "\n"}' file1
0,0,2799,29,1,9,0,0,5,4,


$ awk -F, '{sum=0; for (i=1; i<=NF; i++) { sum+= $i } print [=12=] "," sum}' test
x,y,8,0,0,0,0,0,0,0,8
m,z,0,0,0,0,0,0,0,0,0
a,b,206,1,0,2,0,0,0,0,209
c,d,211,0,0,0,0,0,0,1,212
e,f,8,0,0,1,0,0,0,0,9
g,h,5,0,0,0,0,0,0,0,5
i,j,2,0,0,0,0,0,0,0,2
k,l,36,0,0,0,0,0,0,0,36
m,n,2,0,0,0,0,0,0,0,2
o,p,43,0,0,1,0,0,0,0,44
q,r,2153,28,1,5,0,0,5,3,2195
s,t,96,0,0,0,0,0,0,0,96
u,v,25,0,0,0,0,0,0,0,25

使用 awk 添加列值

adding column values using awk

awk

ksh

gnu