Select 其中 1 个字段的计数大于一个值而另一个字段的计数小于一个值

Question

我正在尝试 return Customers table 中的所有实例，其中 statustype= 'dc' 然后对于这些结果，FC 上的计数 > 1 和 Address1 上的计数是 1.

IE:

FC    Address1
111    abc
111    cde
432    qqq
432    qqq

我需要返回 111 FC 结果，因为它们的 address1 不同。但我不需要返回 432 FC 结果，因为该 FC

的地址不止 1 个

 SELECT *
  FROM Customers
  where FC IN( select FC from Customers where StatusType= 'dc'
  group by FC having COUNT(FC) > 1 and COUNT(Address1) < 2

)
  order by FC, Address1

我也试过 = 1 而不是 < 2

Answer 1

您还需要按 Address1 分组。

SELECT *
FROM Customers
where FC IN( select FC from Customers where StatusType= 'dc'
group by FC, Address1 having COUNT(FC) > 1 and COUNT(Address1) < 2)
order by FC, Address1

Answer 2

尝试使用 Distinct COUNT

SELECT *
FROM   Customers
WHERE  FC IN(SELECT FC
             FROM   Customers
             WHERE  StatusType = 'dc'
             GROUP  BY FC
             HAVING Count(DISTINCT Address1) > 1)
ORDER  BY FC,
          Address1

Answer 3

如果您想要有关具有多个唯一地址的 FC 的详细信息，那么此查询将为您提供：

select c.* from customers c
join (
    select FC
    from customers
    where statustype = 'dc'
    group by fc having count(distinct Address1) > 1
) a on c.FC = a.FC

Select 其中 1 个字段的计数大于一个值而另一个字段的计数小于一个值

Select where Count of 1 field is greater than a value and count of another is less than a value

sql

group-by

count