pytest 在辅助函数中断言自省
pytest assert introspection in helper function
pytest
非常棒 assert introspection
所以很容易找到字符串中的差异,特别是如果差异是白色的 space。现在我使用一个稍微复杂的测试助手,我在许多测试用例中重复使用它。助手也有自己的模块,我想为该模块添加断言内省。
helpers.py:
...
def my_helper():
assert 'abcy' == 'abcx'
test_mycase.py:
from .helpers import my_helper
def test_assert_in_tc():
assert 'abcy' == 'abcx'
def test_assert_in_helper():
my_helper()
测试报告显示测试中断言的有用信息,但 not for asserts within the helper
:
=============================================================== FAILURES ================================================================
___________________________________________________________ test_assert_in_tc ___________________________________________________________
def test_assert_in_tc():
> assert 'abcy' == 'abcx'
E assert 'abcy' == 'abcx'
E - abcy
E ? ^
E + abcx
E ? ^
tests/test_pytest_assert.py:9: AssertionError
_________________________________________________________ test_assert_in_helper _________________________________________________________
def test_assert_in_helper():
> my_helper()
tests/test_pytest_assert.py:13:
_ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _
def my_helper():
> assert 'abcy' == 'abcx'
E AssertionError
tests/helpers.py:258: AssertionError
======================================================= 2 failed in 0.24 seconds ========================================================
作为一种解决方法,我使用断言输出了额外的信息,但输出看起来仍然很奇怪,并使代码崩溃。关于如何在帮助文件中激活 pytest assert introspection 有什么想法吗?
我找到了 different, but related question 不幸的是,到目前为止我无法得到解决方案:
import pytest
from .helpers import my_helper
pytest.register_assert_rewrite('helpers.my_helper')
我不得不像这样将 register_assert_rewrite 放入 tests/__init__.py 中:
import pytest
# we want to have pytest assert introspection in the helpers
pytest.register_assert_rewrite('tests.helpers')
pytest
非常棒 assert introspection
所以很容易找到字符串中的差异,特别是如果差异是白色的 space。现在我使用一个稍微复杂的测试助手,我在许多测试用例中重复使用它。助手也有自己的模块,我想为该模块添加断言内省。
helpers.py:
...
def my_helper():
assert 'abcy' == 'abcx'
test_mycase.py:
from .helpers import my_helper
def test_assert_in_tc():
assert 'abcy' == 'abcx'
def test_assert_in_helper():
my_helper()
测试报告显示测试中断言的有用信息,但 not for asserts within the helper
:
=============================================================== FAILURES ================================================================
___________________________________________________________ test_assert_in_tc ___________________________________________________________
def test_assert_in_tc():
> assert 'abcy' == 'abcx'
E assert 'abcy' == 'abcx'
E - abcy
E ? ^
E + abcx
E ? ^
tests/test_pytest_assert.py:9: AssertionError
_________________________________________________________ test_assert_in_helper _________________________________________________________
def test_assert_in_helper():
> my_helper()
tests/test_pytest_assert.py:13:
_ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _
def my_helper():
> assert 'abcy' == 'abcx'
E AssertionError
tests/helpers.py:258: AssertionError
======================================================= 2 failed in 0.24 seconds ========================================================
作为一种解决方法,我使用断言输出了额外的信息,但输出看起来仍然很奇怪,并使代码崩溃。关于如何在帮助文件中激活 pytest assert introspection 有什么想法吗?
我找到了 different, but related question 不幸的是,到目前为止我无法得到解决方案:
import pytest
from .helpers import my_helper
pytest.register_assert_rewrite('helpers.my_helper')
我不得不像这样将 register_assert_rewrite 放入 tests/__init__.py 中:
import pytest
# we want to have pytest assert introspection in the helpers
pytest.register_assert_rewrite('tests.helpers')