pytest 在辅助函数中断言自省

pytest assert introspection in helper function

pytest 非常棒 assert introspection 所以很容易找到字符串中的差异,特别是如果差异是白色的 space。现在我使用一个稍微复杂的测试助手,我在许多测试用例中重复使用它。助手也有自己的模块,我想为该模块添加断言内省。

helpers.py:

...
def my_helper():
    assert 'abcy' == 'abcx'

test_mycase.py:

from .helpers import my_helper


def test_assert_in_tc():
    assert 'abcy' == 'abcx'


def test_assert_in_helper():
    my_helper()

测试报告显示测试中断言的有用信息,但 not for asserts within the helper:

=============================================================== FAILURES ================================================================
___________________________________________________________ test_assert_in_tc ___________________________________________________________

    def test_assert_in_tc():
>       assert 'abcy' == 'abcx'
E       assert 'abcy' == 'abcx'
E         - abcy
E         ?    ^
E         + abcx
E         ?    ^

tests/test_pytest_assert.py:9: AssertionError
_________________________________________________________ test_assert_in_helper _________________________________________________________

    def test_assert_in_helper():
>       my_helper()

tests/test_pytest_assert.py:13: 
_ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _

    def my_helper():
>       assert 'abcy' == 'abcx'
E       AssertionError

tests/helpers.py:258: AssertionError
======================================================= 2 failed in 0.24 seconds ========================================================

作为一种解决方法,我使用断言输出了额外的信息,但输出看起来仍然很奇怪,并使代码崩溃。关于如何在帮助文件中激活 pytest assert introspection 有什么想法吗?

我找到了 different, but related question 不幸的是,到目前为止我无法得到解决方案:

import pytest
from .helpers import my_helper
pytest.register_assert_rewrite('helpers.my_helper')

我不得不像这样将 register_assert_rewrite 放入 tests/__init__.py 中:

import pytest

# we want to have pytest assert introspection in the helpers
pytest.register_assert_rewrite('tests.helpers')