Guzzle post 嵌套数组的多部分请求

Question

经过一整天的调试和试错，尝试使用 Guzzle6 post 和嵌套数组和资源项搜索一个好的方法。

我在 Guzzle6 文档中发现数据需要 post 和 ['multipart' => []]。当我得到单个数组项时这有效。但是我得到了这样的嵌套数组项。

[
    [firstname] => 'Danny',
    [phone] => [
        [0] => [
            [phone] => 0612345678
        ]
    ]
    [picture] => '/data/...'
]

Guzzle6 需要将其格式设置为 multipart，如下所示。

[
    [
        'name' => 'firstname',
        'contents' => 'Danny'
    ],
    [
        'name' => 'phone[0][phone]
        'contents' => '0612345678'
    ],
    [
        'name' => 'picture',
        'contents' => fopen('....', 'r')
    ]
]

我想不用特殊技巧来解决这个问题。有没有一种好方法可以将带有嵌套数组和资源的 post 数组发送到多部分数组。

Answer 1

是的，有一个更简单的方法。您可以以所需格式将值作为数组发送，并使用 http_build_query.

组合它们

示例：

$params = [
    'firstname' => 'Danny',
    'phone' => [
            'phone' => '0612345678'
               ]
    'picture' => '/data/...'
]


$request_pararms = http_build_query($params);

现在在 Guzzle 中发送 $request_params。

Answer 2

经过一整天的工作，我得到了我的多部分表单数据数组。对于遇到同样问题的每个人，这里是代码。在 $output 中，数据中有一个字段数组。它可以在 ['multipart' => $output] 中与 Guzzle 一起使用。

    $output = [];

    foreach($data as $key => $value){
        if(!is_array($value)){
            $output[] = ['name' => $key, 'contents' => $value];
            continue;
        }

        foreach($value as $multiKey => $multiValue){
            $multiName = $key . '[' .$multiKey . ']' . (is_array($multiValue) ? '[' . key($multiValue) . ']' : '' ) . '';
            $output[] = ['name' => $multiName, 'contents' => (is_array($multiValue) ? reset($multiValue) : $multiValue)];
        }
    }

Answer 3

我在上面使用了@DannyBevers 的回答，但发现它不适用于需要作为多部分发送的深层嵌套数组，所以这里有一个替代解决方案：

// fake nested array to be sent multipart by guzzle
$array = array(
        'title' => 'Test title',
        'content' => 'Test content',
        'id' => 17,
        'Post' => array(

                0 => array(
                        'id' => 100027,
                        'name' => 'Fake post title',
                        'content' => 'More test content ',
                        'Comments' => array (

                                0 => 'My first comment',
                                1 => 'My second comment',
                                2 => 'My third comment'
                        )
                ),
                1 => array(
                        'id' => 100028,
                        'name' => 'Another fake post title',
                        'overall' => 2,
                        'content' => 'Even More test content ',
                        'Comments' => array (

                                0 => 'My other first comment',
                                1 => 'My other second comment',

                        )
                )

        )
);


$flatten = function($array, $original_key = '') use (&$flatten) {

    $output = [];

    foreach ($array as $key => $value) {

        $new_key = $original_key;

        if (empty($original_key)) {

            $new_key .= $key;

        } else {

            $new_key .= '[' . $key . ']';

        }

        if (is_array($value)) {

            $output = array_merge($output, $flatten($value, $new_key));

        } else {

            $output[$new_key] = $value;

        }
    }

    return $output;

};


$flat_array = $flatten($array);

$data = [];

foreach($flat_array as $key => $value) {

    $data[] = [

            'name'  => $key,
            'contents' => $value

    ];


}

$response = $guzzle->request($type, $get, array('multipart' => $data));

Answer 4

因为我遇到了完全相同的问题，并且当我得到集合字段时，我有一个多嵌套级别数组！所以，我需要调整这里发布的功能。

我合并了@John 和@DannyBevers 解决方案以获得 name 参数的完整密钥和 contents 参数的值。然后，我在 multipart key

下添加了函数结果

函数：

private function flatten($array, $prefix = "[", $suffix = "]") {
    global $i;
    $result = array();
    foreach($array as $key=>$value) {
        if(is_array($value)) {
            if($i == 0) {
                $result = $result + $this->flatten($value, $key.$prefix, $suffix);
            }
            else {
                foreach ($this->flatten($value, $prefix . $key . $suffix."[", $suffix) as $k => $v){
                    $result[] = $v;
                }
            }
        }
        else {                
            if($value instanceof UploadedFile){
                $result[] = ["name" => $prefix.$key.$suffix,
                    "filename" => $value->getClientOriginalName(),
                    "Mime-Type" => $value->getMimeType(),
                    "contents" => fopen($value->getPathname(), "r")];
            }
            else {
                $result[] = ["name" => $prefix . $key . $suffix, "contents" => $value];
            }
        }
        $i++;
    }
    return $result;
}

输出：

@Danny Bevers 解决方案将输出：

在我的项目中，我的函数不会抛出任何错误，而 @DannyBevers 的会抛出任何错误。

希望对您有所帮助！

Answer 5

为它取漂亮的函数:

function getFlatten($key, array $data, $result = [])
{
    foreach ($data as $subKey => $value) {
        $subKey = $key . '[' . $subKey . ']';
        if (\is_array($value)) {
            $result = $this->getFlatten($subKey, $value, $result);
        } else {
            $result[] = ['name' => $subKey, 'contents' => $value];
        }
    }

    return $result;
}

例子

   $data = [
        'first' => [
            'second' => ['third' => 12, 'third_a' => 13],
            'second_2' => 3,
            'second_3' => ['third_2' => ['fours' => 15]],
        ],
    ];

if (is_array($data)) {
    $request = getFlatten('main_key', $data)
}

输出

    0 => [
        'name' => 'main_key[first][second][third]'
        'contents' => 12
    ]
    1 => [
        'name' => 'main_key[first][second][third_a]'
        'contents' => 13
    ]
    2 => [
        'name' => 'main_key[first][second_2]'
        'contents' => 3
    ]
    3 => [
        'name' => 'main_key[first][second_3][third_2][fours]'
        'contents' => 15
    ]

Answer 6

None 以上解决方案对我有用，因为我的数组结构具有顶级值和嵌套。

我创建了解决问题的 Gist：https://gist.github.com/matthew-inamdar/a17701f948770ac0a55acd9d12445645

您可以简单地使用以下内容：

$data = [
    'name' => 'John',
    'language' => [
        'main' => 'English',
        'secondary' => [
            0 => 'Spanish',
            1 => 'German'
        ]
    ],
];

$flattened = (new Flatten())->flatten($data);

$flattened = [
    ['name' => 'name', 'contents' => 'John'],
    ['name' => 'language[main]', 'contents' => 'English'],
    ['name' => 'language[secondary][0]', 'contents' => 'Spanish'],
    ['name' => 'language[secondary][1]', 'contents' => 'German']
];

Answer 7

@见https://github.com/guzzle/guzzle/issues/1679#issuecomment-342233663

使用http_build_query 将名称扁平化，然后构建多部分。

$multipart = [];
$vars = explode('&', http_build_query($postData));
foreach ($vars as $var) {
    list($nameRaw, $contentsRaw) = explode('=', $var);
    $name = urldecode($nameRaw);
    $contents = urldecode($contentsRaw);
    $multipart[] = ['name' => $name, 'contents' => $contents];
}

Answer 8

示例数据：

$array = [
  "doc_id" => 2,
  "data" => [
    [
      "field" => "10"
      "value" => "test10"
    ],
    [
      "field" => "11"
      "value" => "test11"
    ]
  ]
]

编码多维数组

$outputArray = explode('&', urldecode(http_build_query($array)))

输出：

array[
  0 => "doc_id =2",
  1 => "data[0][field]=10",
  2 => "data[0][value]=test10",
  3 => "data[1][field]=11",
  4 => "data[1][value]=test11"
]

添加Post数据：

foreach ($outputArray as $data) {
    list($key, $value) = explode('=', $data);
    $postData[] = ['name' => $key, 'contents' => $value];
}

Guzzle post 嵌套数组的多部分请求

Guzzle post multipart request with nested array

php

arrays

laravel

guzzle

guzzle6