Unix shell - 意外标记“完成”附近的语法错误

Question

下面是我的代码。

#!/bin/ksh
curdate=$(date '+%d%h,%Y')
while read line;
do
  echo "$line" > new10.txt
  str0=$(cut -f 2 new10.txt)
  str01=$(cut -f 1 -d ',' new10.txt)
  str1=$(cut -f 2 -d ',' new10.txt)
  str2=$(cut -c 3 $str1)
  if [ $str2=':' ];
  then
    str2=',2016'
    finalstr=$str01$str2
    if [ '01jan2017' -le $finalstr -le $curdate ];
    then
      finalstr1=$str01',2017'
    else
      finalstr1=$str01',2016'
      echo $finalstr1 > datefinal.txt
    fi
done < /export/home/islams/PISAS/userwiseutil/date.txt

我收到以下错误： date1.sh：第 22 行：意外标记附近的语法错误 done' date1.sh: line 22:完成 < /export/home/islams/PISAS/userwiseutil/date.txt'

Answer 1

#!/bin/ksh
curdate=$(date '+%d%h,%Y')
while read line;
do
  echo "$line" > new10.txt
  str0=$(cut -f 2 new10.txt)
  str01=$(cut -f 1 -d ',' new10.txt)
  str1=$(cut -f 2 -d ',' new10.txt)
  str2=$(cut -c 3 $str1)
  if [ $str2=':' ];
  then
    str2=',2016'
    finalstr=$str01$str2
    if [ '01jan2017' -le $finalstr -le $curdate ];
    then
      finalstr1=$str01',2017'
    else
      finalstr1=$str01',2016'
      echo $finalstr1 > datefinal.txt
    fi
  fi #You missed this
done < /export/home/islams/PISAS/userwiseutil/date.txt

你错过了一个 fi

Unix shell - 意外标记“完成”附近的语法错误

Unix shell - syntax error near unexpected token `done'

unix

ksh