psql 查询计数应该是条件下的全局字段

Question

Table 架构和数据：

CREATE TABLE aaa (
    nall integer NOT NULL,
    ladata date NOT NULL,
    txt text,
    CONSTRAINT aaa_pkey PRIMARY KEY (nall, ladata)
 )

数据：

2 | '2016-01-01' | 'a'
2 | '2016-02-02' | 'a'
5 | '2016-03-03' | 'a'
6 | '2016-03-03' | 'b'

查询：

select txt,
       count(txt),
       min(ladata),  
       (select  count(txt) from aaa where txt !='') 
from aaa
where ladata > (select MIN(ladata) from aaa ) and nall != 2
group by txt

http://sqlfiddle.com/#!15/db06b1/1

到return:

txt   count   min     count
b     1   March, 03 2016 00:00:00     1
a     3   March, 03 2016 00:00:00     3

我需要来自具有相同 txt 的行的部分 count 和来自 nall[=37 的行的日期=] 不同于 2.

但保持 returning 从整个 table:
计数

txt count min count b 1 March, 03 2016 00:00:00 4 a 1 March, 03 2016 00:00:00 4

我正在使用 postgresql 9.6

Answer 1

这是解决方案：

select a.txt, count(a.txt), min(ladata)
    , (select  count(txt) from aaa b where b.txt =a.txt ) 
from aaa a  
where ladata>(select MIN(ladata) from aaa) and nall != 2  
group by txt

psql 查询计数应该是条件下的全局字段

psql query count should be global field on condition

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