C 中的指针和字符串输出

Question

我试图理解为什么以下代码会产生 BCD123 123.

的输出

void f(char *p)
{
    *p += 1;
}

int main()
{
    int i;
    char a[] = "ABC" "123";
    char *p = a;

    for (i = 0; i < 3; i++)
        f(p++);

    printf("%s ", a);

    printf("%s ", p);

    return 0;
}

Answer 1

void f(char *p)
{
    *p += 1;
}

将传入的字符加 1。'A' + 1 = 'B' 等。查看 ascii table http://www.asciitable.com/

第 2 部分

   char a[] = "ABC" "123";
// is the same as 
   char a[] = "ABC123";
      for (i = 0; i < 3; i++)
            f(p++); <<<<===== moves p along the string 3 places (once for each loop)

        printf("%s ", a);

        printf("%s ", p);  <<< p now points at 4th char

C 中的指针和字符串输出

Pointer and String Outputs in C

c

arrays

string

pointers

output