快捷代码(根据数量隐藏视图)
Shortcut the code (hide views based on count of number)
下面的最佳代码是什么,代码运行良好,没有问题,我正在寻找更好的代码编写方式,有 11 个视图和一定数量的用户,所以我需要隐藏基于 11 个可用用户的视图假设我们有 11 个用户,只有 2 个可用,所以它将是 11 个中的 2 个。该应用程序将隐藏第一个视图和第二个视图,但不会隐藏从 3 到 11 的视图,依此类推
NSInteger countOfViews = 2;
if (countOfViews == 1) {
UIView *viewtag1 = (UIView *)[self.leftScrollView viewWithTag:1000];
UIView *viewtag2 = (UIView *)[self.leftScrollView viewWithTag:2000];
UIView *viewtag3 = (UIView *)[self.leftScrollView viewWithTag:3000];
UIView *viewtag4 = (UIView *)[self.leftScrollView viewWithTag:4000];
UIView *viewtag5 = (UIView *)[self.leftScrollView viewWithTag:5000];
UIView *viewtag6 = (UIView *)[self.leftScrollView viewWithTag:6000];
UIView *viewtag7 = (UIView *)[self.leftScrollView viewWithTag:7000];
UIView *viewtag8 = (UIView *)[self.leftScrollView viewWithTag:8000];
UIView *viewtag9 = (UIView *)[self.leftScrollView viewWithTag:9000];
UIView *viewtag10 = (UIView *)[self.leftScrollView viewWithTag:10000];
UIView *viewtag11 = (UIView *)[self.leftScrollView viewWithTag:11000];
viewtag1.hidden = YES;
viewtag2.hidden = NO;
viewtag3.hidden = NO;
viewtag4.hidden = NO;
viewtag5.hidden = NO;
viewtag6.hidden = NO;
viewtag7.hidden = NO;
viewtag8.hidden = NO;
viewtag9.hidden = NO;
viewtag10.hidden = NO;
viewtag11.hidden = NO;
}
if (countOfViews == 2) {
UIView *viewtag1 = (UIView *)[self.leftScrollView viewWithTag:1000];
UIView *viewtag2 = (UIView *)[self.leftScrollView viewWithTag:2000];
UIView *viewtag3 = (UIView *)[self.leftScrollView viewWithTag:3000];
UIView *viewtag4 = (UIView *)[self.leftScrollView viewWithTag:4000];
UIView *viewtag5 = (UIView *)[self.leftScrollView viewWithTag:5000];
UIView *viewtag6 = (UIView *)[self.leftScrollView viewWithTag:6000];
UIView *viewtag7 = (UIView *)[self.leftScrollView viewWithTag:7000];
UIView *viewtag8 = (UIView *)[self.leftScrollView viewWithTag:8000];
UIView *viewtag9 = (UIView *)[self.leftScrollView viewWithTag:9000];
UIView *viewtag10 = (UIView *)[self.leftScrollView viewWithTag:10000];
UIView *viewtag11 = (UIView *)[self.leftScrollView viewWithTag:11000];
viewtag1.hidden = YES;
viewtag2.hidden = YES;
viewtag3.hidden = NO;
viewtag4.hidden = NO;
viewtag5.hidden = NO;
viewtag6.hidden = NO;
viewtag7.hidden = NO;
viewtag8.hidden = NO;
viewtag9.hidden = NO;
viewtag10.hidden = NO;
viewtag11.hidden = NO;
}
/*
till if (countOfViews == 11)
*/
NSInteger countOfViews = 2;
for (int i = 1; i <= 11; i++) {
UIView *view = (UIView *)[self.leftScrollView viewWithTag:i * 1000];
view.hidden = (i <= countOfViews);
}
下面的最佳代码是什么,代码运行良好,没有问题,我正在寻找更好的代码编写方式,有 11 个视图和一定数量的用户,所以我需要隐藏基于 11 个可用用户的视图假设我们有 11 个用户,只有 2 个可用,所以它将是 11 个中的 2 个。该应用程序将隐藏第一个视图和第二个视图,但不会隐藏从 3 到 11 的视图,依此类推
NSInteger countOfViews = 2;
if (countOfViews == 1) {
UIView *viewtag1 = (UIView *)[self.leftScrollView viewWithTag:1000];
UIView *viewtag2 = (UIView *)[self.leftScrollView viewWithTag:2000];
UIView *viewtag3 = (UIView *)[self.leftScrollView viewWithTag:3000];
UIView *viewtag4 = (UIView *)[self.leftScrollView viewWithTag:4000];
UIView *viewtag5 = (UIView *)[self.leftScrollView viewWithTag:5000];
UIView *viewtag6 = (UIView *)[self.leftScrollView viewWithTag:6000];
UIView *viewtag7 = (UIView *)[self.leftScrollView viewWithTag:7000];
UIView *viewtag8 = (UIView *)[self.leftScrollView viewWithTag:8000];
UIView *viewtag9 = (UIView *)[self.leftScrollView viewWithTag:9000];
UIView *viewtag10 = (UIView *)[self.leftScrollView viewWithTag:10000];
UIView *viewtag11 = (UIView *)[self.leftScrollView viewWithTag:11000];
viewtag1.hidden = YES;
viewtag2.hidden = NO;
viewtag3.hidden = NO;
viewtag4.hidden = NO;
viewtag5.hidden = NO;
viewtag6.hidden = NO;
viewtag7.hidden = NO;
viewtag8.hidden = NO;
viewtag9.hidden = NO;
viewtag10.hidden = NO;
viewtag11.hidden = NO;
}
if (countOfViews == 2) {
UIView *viewtag1 = (UIView *)[self.leftScrollView viewWithTag:1000];
UIView *viewtag2 = (UIView *)[self.leftScrollView viewWithTag:2000];
UIView *viewtag3 = (UIView *)[self.leftScrollView viewWithTag:3000];
UIView *viewtag4 = (UIView *)[self.leftScrollView viewWithTag:4000];
UIView *viewtag5 = (UIView *)[self.leftScrollView viewWithTag:5000];
UIView *viewtag6 = (UIView *)[self.leftScrollView viewWithTag:6000];
UIView *viewtag7 = (UIView *)[self.leftScrollView viewWithTag:7000];
UIView *viewtag8 = (UIView *)[self.leftScrollView viewWithTag:8000];
UIView *viewtag9 = (UIView *)[self.leftScrollView viewWithTag:9000];
UIView *viewtag10 = (UIView *)[self.leftScrollView viewWithTag:10000];
UIView *viewtag11 = (UIView *)[self.leftScrollView viewWithTag:11000];
viewtag1.hidden = YES;
viewtag2.hidden = YES;
viewtag3.hidden = NO;
viewtag4.hidden = NO;
viewtag5.hidden = NO;
viewtag6.hidden = NO;
viewtag7.hidden = NO;
viewtag8.hidden = NO;
viewtag9.hidden = NO;
viewtag10.hidden = NO;
viewtag11.hidden = NO;
}
/*
till if (countOfViews == 11)
*/
NSInteger countOfViews = 2;
for (int i = 1; i <= 11; i++) {
UIView *view = (UIView *)[self.leftScrollView viewWithTag:i * 1000];
view.hidden = (i <= countOfViews);
}