Logstash 仅发送 json

Question

我正在通过 logstash 发送此日志

2017-02-27T13:00:07+01:00    test    {"createdAt":"2017-02-27T13:00:07+0100","cluster":"undefined","nodeName":"undefined","nodeIP":"10.11.11.50","clientIP":"10.11.11.72","customerId":1,"identityId":332,"appType":"admin","eventGroup":"education","eventName":"insert","eventData":{"education_insert":{"type":"course","data":{"education_id":2055,"education":{"id":2055,"customer_id":1,"creator_id":332,"type":"course","status":"new","is_featured":false,"enroll_deadline":null,"complete_deadline":null,"count_view":0,"count_like":0,"meta_title":"test Course - progress","meta_description":"test Course - progress","discoverable":"everyone","progress_max":0,"instructor_ids":[332],"tag_ids":[135],"discoverable_group_ids":[],"category_ids":[14],"audits":null,"instructors":null,"creator":null,"lessonGroups":null,"categories":null},"duration":"quick"}}},"scopeType":"education","scopeId":"2055"}

如何删除 2017-02-27T13:00:07+01:00 和 test.app.event

Answer 1

您需要使用 grok 提取消息的 json 部分，然后使用 json 过滤器将提取的 json 转换为事件。最后，您需要使用 mutate 删除您在最终事件中不需要的任何字段（例如，message）。

Answer 2

您可以使用 regex 模式来仅获得 json。 regex 模式应该在您的 patterns 文件中：

模式可能如下所示：

REQUIREDDATA {([^}]*)}([^}]*)([^}]*)}}}([^}]*)} <-- this extracts only your json part

测试的正则表达式pattern。

此后您可以在 grok match:

中使用该模式

grok {
    patterns_dir => ["/pathto/patterns"]
    match => { "message" => "^%{REQUIREDDATA:new}" }            
}

现在消息只有日志行中的 JSON 部分，因此您现在可以通过 logstash 将它们推送到 ES。以上只是一个示例，方便大家复现。

希望对您有所帮助！

Answer 3

我用过这个并为我工作 :) 感谢帮助

input { kafka { bootstrap_servers=>"localhost:9092" topics=>"test"}}
filter{
grok {
    match => { "message" => "%{TIMESTAMP_ISO8601:timestamp}\t%{GREEDYDATA:topic}\t%{GREEDYDATA:json}" }
  }
  json {
     source => "json"
     remove_field => ["timestamp","topic","json","message","@version","@timestamp","tags"]
  }
 }
output{ elasticsearch {hosts=>["127.0.0.1:9200"] document_type=>"app_stats" index=>"test"}}

Logstash 仅发送 json

Logstash send only json

json

logstash

logstash-grok