循环中的多个查询解析云代码

Question

我很难理解承诺，我确定我需要为此使用它们，但我不知道如何使用，其他答案对我根本没有帮助。

我想遍历一个数组，查询数组每个值的所有结果，然后在计算这些结果的平均值后，将平均值添加到一个数组中。每次迭代后，此数组作为响应发送。

这是我的代码，可以帮助理解我的意思：

Parse.Cloud.define('getScorePeopleArray', function(request, response) {

    var peopleArray = request.params.peoplearray;
    var query = new Parse.Query("Scores");
    var resultat;
    var index, len;
    var resultarray = [];
    var people;

    for (index = 0, len = peopleArray.length; index < len; ++index) {
      people = peopleArray[index];
      query.equalTo("People",people);
      query.find({
        success: function(results) {
          var sum = 0;
          for (var i = 0; i < results.length; ++i) {
           sum += results[i].get("Score");
          }
          resultat = (sum / results.length)*5;
          if(!resultat){
            resultarray.push("null");
          }else{
            resultarray.push(resultat);
          }
        },
        error: function() {
          response.error("score lookup failed");
        }
    }).then();
  }
  response.success(resultarray);  
});

当然 response.success 不会在每次查询完成时调用，而是尽快调用（因为如果我是对的，查询是异步的）。我知道我必须用承诺来改变它，但我完全不明白这是如何工作的。

提前致谢！

Answer 1

var _ = require('underscore');

Parse.Cloud.define('getScorePeopleArray', function(request, response) {

 var peopleArray = request.params.peoplearray; // what is this an array of?
 var resultArray = [];

  return Parse.Promise.as().then(function() { // this just gets the ball rolling
    var promise = Parse.Promise.as(); // define a promise

    _.each(peopleArray, function(people) { // use underscore, its better :)
      promise = promise.then(function() { // each time this loops the promise gets reassigned to the function below

        var query = new Parse.Query("Scores");
        query.equalTo("People", people); // is this the right query syntax?
        return query.find().then(function(results) { // the code will wait (run async) before looping again knowing that this query (all parse queries) returns a promise. If there wasn't something returning a promise, it wouldn't wait.

          var sum = 0;
          for (var i = 0; i < results.length; i++) {
            sum += results[i].get("Score");
          }
          var resultat = (sum / results.length) * 5;

          if (!resultat){
            resultArray.push("null");
          } else {
            resultArray.push(resultat);
          }

          return Parse.Promise.as(); // the code will wait again for the above to complete because there is another promise returning here (this is just a default promise, but you could also run something like return object.save() which would also return a promise)

        }, function (error) {
          response.error("score lookup failed with error.code: " + error.code + " error.message: " + error.message);
        });
      }); // edit: missing these guys
    });
    return promise; // this will not be triggered until the whole loop above runs and all promises above are resolved

  }).then(function() {
    response.success(resultArray); // edit: changed to a capital A
  }, function (error) {
    response.error("script failed with error.code: " + error.code + " error.message: " + error.message);
  });
});

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