访问 - row_number 函数？

Question

我有这个查询，它在 postgres

上给了我想要的结果

SELECT
  t.*,
  ROW_NUMBER() OVER (PARTITION BY t."Internal_reference", t."Movement_date" ORDER BY t."Movement_date") AS "cnt"
FROM (SELECT
  "Internal_reference",
  MAX("Movement_date") AS maxtime
FROM dw."LO-D4_Movements"
GROUP BY "Internal_reference") r
INNER JOIN dw."LO-D4_Movements" t
  ON t."Movement_date" = r.maxtime
  AND t."Internal_reference" = r."Internal_reference"

问题是我必须在 Access 上翻译上面的查询，其中分析函数不存在...

我用这个 answer 构建了下面的查询

SELECT 
      t."Internal_reference",
      t.from_code,
      t.to_code,
      t."Movement_date",
      t.shipment_number,
      t."PO_number",
      t."Quantity",
      t."Movement_value",
      t."Site",
      t."Import_date",
  COUNT(*) AS "cnt"
 FROM (
      SELECT "Internal_reference",
      MAX("Movement_date") AS maxtime
      FROM dw."LO-D4_Movements"
      GROUP BY "Internal_reference") r
LEFT OUTER JOIN dw."LO-D4_Movements" t
        ON t."Movement_date" = r.maxtime AND t."Internal_reference" = r."Internal_reference"
GROUP BY
      t.from_code,
      t.to_code,
      t."Movement_date",
      t.shipment_number,
      t."PO_number",
      t."Quantity",
      t."Movement_value",
      t."Site",
      t."Import_date",
      t."Internal_reference" 
ORDER BY t.from_code

问题是我在 cnt 列中只有 1。

我试图通过删除 internal_reference 来调整它（见下文）

SELECT 
      t.from_code,
      t.to_code,
      t."Movement_date",
      t.shipment_number,
      t."PO_number",
      t."Quantity",
      t."Movement_value",
      t."Site",
      t."Import_date",
  COUNT(*) AS "cnt"
 FROM (
      SELECT "Internal_reference",
      MAX("Movement_date") AS maxtime
      FROM dw."LO-D4_Movements"
      GROUP BY "Internal_reference") r
LEFT OUTER JOIN dw."LO-D4_Movements" t
        ON t."Movement_date" = r.maxtime AND t."Internal_reference" = r."Internal_reference"
GROUP BY
      t.from_code,
      t.to_code,
      t."Movement_date",
      t.shipment_number,
      t."PO_number",
      t."Quantity",
      t."Movement_value",
      t."Site",
      t."Import_date" 
ORDER BY t.from_code

然而，结果更糟。 cnt 正在增长，但它给了我错误的 cnt

非常欢迎任何帮助，因为我正在慢慢失去理智。

谢谢

编辑： 请找到 sqlfiddle

Answer 1

据我所知，这在 MS Access 中是一个真正的痛苦。一种方法是相关子查询，但你需要在每一行上有一个唯一的 id 列：

SELECT t.*,
       (SELECT COUNT(*)
        FROM (SELECT "Internal_reference", MAX("Movement_date") AS maxtime
              FROM dw."LO-D4_Movements"
              GROUP BY "Internal_reference"
             ) as t2
        WHERE t2."Internal_reference" AND t."Internal_reference" AND

              t2."Movement_date" = t."Movement_date" AND
              t2.?? <= t.??
       ) as cnt
FROM (SELECT "Internal_reference", MAX("Movement_date") AS maxtime
      FROM dw."LO-D4_Movements"
      GROUP BY "Internal_reference"
     ) r INNER JOIN
     dw."LO-D4_Movements" t
     ON t."Movement_date" = r.maxtime AND
        t."Internal_reference" = r."Internal_reference";

?? 用于 ID 或创建日期或允许计算行数的内容。

Answer 2

我认为 Gordon-Linoff 的代码接近您想要的，但是有一些拼写错误我无法在不重写的情况下更正，所以这是我的尝试

SELECT
    t1.Internal_reference,
    t1.Movement_date,
    t1.PO_Number as Combination_Of_Columns_Which_Make_This_Unique,
    t1.Other_columns,
    Count(1) AS Cnt
FROM
    ([LO-D4_Movements] AS t1
    INNER JOIN [LO-D4_Movements] AS t2 ON
        t1.Internal_reference = t2.Internal_reference AND
        t1.Movement_date = t2.Movement_date)
    INNER JOIN (
        SELECT
            t3.Internal_reference,
            MAX(t3.Movement_date) AS Maxtime
        FROM
            [LO-D4_Movements] AS t3
        GROUP BY
            t3.Internal_reference
            )  AS r ON
        t1.Internal_reference = r.Internal_reference AND
        t1.Movement_date = r.Maxtime
WHERE  
    t1.PO_Number>=t2.PO_Number
GROUP BY
    t1.Internal_reference,
    t1.Movement_date,t1.PO_Number,
    t1.Other_columns
ORDER BY
    t1.Internal_reference,
    t1.Movement_date,
    Count(1);

除了max(movement_date)子查询之外，主table被引入了两次。一个版本是显示在结果中的版本，另一个版本是统计记录生成序列号的版本。

Gordon 说您需要为每一行设置一个唯一的 ID 列。如果 "column" 你的意思是也包括派生列，那是真的。此外，它只需要在 "internal_reference" 和 "Movement_date".

的任意组合中是唯一的

我假设 PO_Number 就足够了，这可能是错误的。如果不是，则将其与其他字段（和一些定界符）连接起来，使其独一无二。 where 子句将需要更新以比较 "Combination of Columns which make this unique".

的 t1 和 t2

如果没有可用的合适组合，我不确定如果没有 VBA and/or temp tables 是否可以按照 The-Gambill 的建议完成。

访问 - row_number 函数？

access - row_number function?

sql

postgresql

ms-access

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