如何将字符串的每个单词放入 Swift 中的数组？

Question

是否可以将字符串的每个单词放入Swift中的数组？

例如：

var str = "Hello, Playground!"

至：

var arr = ["Hello","Playground"]

谢谢:)

Answer 1

edit/update:

Xcode 10.2 • Swift 5 或更高

我们可以使用集合拆分方法

扩展 StringProtocol

func split(maxSplits: Int = Int.max, omittingEmptySubsequences: Bool = true, whereSeparator isSeparator: (Character) throws -> Bool) rethrows -> [Self.SubSequence]

将 omittingEmptySubsequences 设置为 true 并将闭包作为谓词传递。我们还可以利用新的 Character 属性 isLetter 来拆分字符串。

extension StringProtocol {
    var words: [SubSequence] {
        return split { ![=11=].isLetter }
    }
}

let sentence = "• Hello, Playground!"
let words = sentence.words // ["Hello", "Playground"]

Answer 2

当字符串中有多个连续空格时，最后一个解决方案（来自 Leo）将在数组中创建空元素。它还会合并由“-”分隔的单词，并将行尾字符作为单词处理。

这个不会：

extension String 
{    
    var wordList: [String] 
    {
       return componentsSeparatedByCharactersInSet(NSCharacterSet.alphanumericCharacterSet().invertedSet).filter({[=10=] != ""})
    }
}

Answer 3

目前这两个答案都不适用于 Swift 4，但以下内容可以解决 OP 的问题，希望也能解决您的问题。

extension String {
    var wordList: [String] {
        return components(separatedBy: CharacterSet.alphanumerics.inverted).filter { ![=10=].isEmpty }
    }
}

let string = "Hello, Playground!"
let stringArray = string.wordList
print(stringArray) // ["Hello", "Playground"]

还有一个带有数字和双字的较长短语 space:

let biggerString = "Hello, Playground! This is a  very long sentence with 123 and other stuff in it"
let biggerStringArray = biggerString.wordList
print(biggerStringArray)
// ["Hello", "Playground", "This", "is", "a", "very", "long", "sentence", "with", "123", "and", "other", "stuff", "in", "it"]

如何将字符串的每个单词放入 Swift 中的数组？

How can I put each word of a string into an array in Swift?

arrays

string

swift