由于 "View The Full list" 按钮,最多 10 个项目

Max of 10 items due to "View The Full list" button

link = http://fortune.com/worlds-most-admired-companies/2016/

所以,我想要 div 内的所有 'href' 和已知的 'class name' 我无法摆脱这个:

import bs4 as bs
import urllib.request

raw = urllib.request.urlopen('http://fortune.com/worlds-most-admired-companies/2016/')
soup = bs.BeautifulSoup(raw, 'lxml')

listdiv = soup.find('div', clsss_="company-franchise-result-content current")

for url in listdiv.find_all('a'):
    print(url.get('href'))

我以前用过:

for a in soup.find_all('a'):
    print(a.get('href'))

有效,但只有 returns 10 个项目,从苹果到通用电气。即使当我输入 link 时,当我单击 "View the Full list" 按钮时也会得到。 我对 JSON 的工作原理一无所知,但看起来这是朝着那个方向发展的。

完整的数据其实在HTML里面。它就在 script 标签内的 JavaScript 对象内。您可以找到此 script 标记,获取它的文本,提取 JSON 字符串,将其加载到 Python 数据结构中 json.loads() 并获取所需数据:

In [1]: from bs4 import BeautifulSoup

In [2]: import json

In [3]: import re

In [4]: url = "http://fortune.com/worlds-most-admired-companies/2016/"

In [5]: response = requests.get(url)

In [6]: soup = BeautifulSoup(response.content, "lxml")   

In [7]: pattern = re.compile(r"var fortune_wp_vars = ({.*?});", re.DOTALL | re.MULTILINE)

In [8]: script = soup.find("script", text=pattern)   

In [9]: data = json.loads(pattern.search(script.get_text()).group(1))  

In [10]: companies = data["bootstrap"]["franchise"]["filtered_sorted_data"]

In [11]: for company in companies:
    ...:     print(company["title"])
    ...:     
Apple
Alphabet
...
Yum Brands
ZF Friedrichshafen
Zurich Insurance Group