Node.js 承诺:异步推送到数组并保存

Node.js Promises: Push to array asynchronously & save

我目前正在尝试从我通过请求收到的项目列表中推送到一个数组(Mongo 模型中的属性)。从这些项目中,我遍历它们以查看数据库中当前有哪一个,如果不是这样,那么我创建一个新项目并尝试保存它。我正在使用 promises 来完成此任务,但我无法弄清楚为什么在所有 promise 都已履行后数组为空。

var q     = require('q');

var items_to_get = ['1', '2', '3']; // example array

var trans = new Transaction({
    items   : []
});

var promises = [];

for (var i = 0; i < items_to_get.length; i++) {

  var ith = i; //save current i, kinda hacky
  var deferred = q.defer(); //init promise

  //find an existing item
  Item.findOne({simcode: items_to_get[ith]}, function(err, item) {
      trans.items.push(item); // push item to transaction
      deferred.resolve(item); // resolve the promise
  });
  promises.push(deferred); // add promise to array, can be rejected or   fulfilled
};

q.allSettled(promises).then(function(result) {
  console.log(trans.items); //is empty
  trans.save();
}

编辑 已解决:下面的代码,基于http://jsbin.com/bufecilame/1/edit?html,js,output ..致谢@macqm

var items_to_get = ['1', '2', '3'];
var promises     = []; //I made this global

items_to_get.forEach(item) {
  upsertItem(item);
}

q.allSettled(promises).then(function(result) {
  //loop through array of promises, add items 
  result.forEach(function(res) { 
    if (res.state === "fulfilled") {
      trans.items.push(res.value);
    }
  });
  trans.save();
  promises = []; //empty array, since it's global.
}

//moved main code inside here
function upsertItem(item) {
  var deferred = q.defer(); //init promise
  //find an existing item
  Item.findOne({simcode: item}, function(err, item) {
    deferred.resolve(item); // resolve the promise
    // don't forget to handle error cases
    // use deffered.reject(item) for those
  });
  promises.push(deferred); // add promise to array
}

而不是

promises.push(deferred);

...尝试...

promises.push(deferred.promise);

此外,由于您的 promise 正在解析无论如何都保存的项目,您可以使用 q.allSettled(...) 的结果作为您的项目:

q.allSettled(promises).then(function(results) {
    trans.items = results;
    trans.save();
});

这就是我在没有任何第 3 方库的情况下的做法。

因为我只是需要推迟,而且我正在使用 ES2017,所以我认为最好不要让不必要的依赖关系过于复杂。

'use strict';

/**
 * @param {function(*)} callee
 * @param {Array} args
 * @returns {Promise.<*>}
 */
const defer = (callee, args) => {
    return new Promise(resolve => {
        resolve(callee(...args));
    });
};

/**
 * @param {Number} one
 * @param {Number} two
 * @param {Number} timeout
 * @returns {Promise.<Number>}
 */
const asyncFunction = (one, two, timeout) => {
    return new Promise(resolve => {
        setTimeout(resolve, timeout, one + two);
    });
};

let promises = [];
promises.push(defer(asyncFunction, [3, 7, 0])); // returns immediately
promises.push(defer(asyncFunction, [10, 20, 100])); // returns after 100ms
promises.push(defer(asyncFunction, [55, 45, 50])); // returns after 50ms

Promise.all(promises).then(results => {
    console.log(results);
});

运行上面的代码,你会得到[ 10, 30, 100 ]