如何根据颜色范围检查 RGB 颜色？

Question

我正在编写一个 python 脚本，我需要用这种方式检查 3 种颜色的颜色代码：红色、黄色和绿色：

if (255,255,255)  is in green range:
    print("green")
else if (255,255,255)  is in yellow range:
    print("yellow")
else if (255,255,255)  is in red range:
    print("red")
else:
    print("none")

我遇到的问题是如何查看它是否 is in yellow range?

如有任何建议，我们将不胜感激。

编辑

下图代表我对黄绿红的感觉：

Answer 1

这是一个简单的解决方案：

KNOWN_COLORS = {"Red": (255, 0, 0), "Yellow": (255, 255, 0), "Green": (0, 255, 0)}

def color_difference (color1, color2) -> int:
    """ calculate the difference between two colors as sum of per-channel differences """
    return sum([abs(component1-component2) for component1, component2 in zip(color1, color2)])


def get_color_name(color) -> str:
    """ guess color name using the closest match from KNOWN_COLORS """
    differences =[
        [color_difference(color, known_color), known_name]
        for known_name, known_color in KNOWN_COLORS.items()
    ]
    differences.sort()  # sorted by the first element of inner lists
    return differences[0][1]  # the second element is the name


my_color = (123, 234, 100)

print(get_color_name(my_color))

# zero copyrights / public domain

数字，my_color = (123, 234, 100)最接近的匹配是绿色:)

Answer 2

将颜色转换为 HSL 并参考像 this one 这样的色轮来选择您对黄色、红色和绿色的定义，特别是 H 值。

如何根据颜色范围检查 RGB 颜色？

How to check RGB colors against a color range?

python

rgb