Android - 文本文件 - 网络服务器
Android - textfile- webserver
我正在做一个 android 应用程序,我想从服务器 (http://10.0.2.2:8080/myserver/arquivo.txt) 读取一个文本文件并在我的应用程序中显示该文本。
我不知道该怎么做。
有人可以帮忙吗?
您可以使用此代码获取响应:
String textFileUrl = "http://10.0.2.2:8080/myserver/arquivo.txt"
String textFileText;
Request httpRequest = new Request();
httpRequest.execute(textFileUrl);
try {
textFileText = httpRequest.get(5000, TimeUnit.MILLISECONDS);
} catch (InterruptedException | ExecutionException | TimeoutException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
System.out.println("The online text file contains: " + textFileText);
TextView textView = (TextView)findViewById(R.id.textview);
textView.setText(textFileText);
创建一个名为 Request.java 的新文件:
import java.io.ByteArrayOutputStream;
import java.io.IOException;
import org.apache.http.HttpResponse;
import org.apache.http.HttpStatus;
import org.apache.http.StatusLine;
import org.apache.http.client.ClientProtocolException;
import org.apache.http.client.HttpClient;
import org.apache.http.client.methods.HttpGet;
import org.apache.http.impl.client.DefaultHttpClient;
import android.os.AsyncTask;
public class Request extends AsyncTask<String, String, String>{
HttpResponse response = null;
public Request(){
}
@Override
protected String doInBackground(String... uri) {
HttpClient httpclient = new DefaultHttpClient();
String responseString = null;
try {
response = httpclient.execute(new HttpGet(uri[0]));
StatusLine statusLine = response.getStatusLine();
if(statusLine.getStatusCode() == HttpStatus.SC_OK){
ByteArrayOutputStream out = new ByteArrayOutputStream();
response.getEntity().writeTo(out);
out.close();
responseString = out.toString();
} else{
//Closes the connection.
response.getEntity().getContent().close();
throw new IOException(statusLine.getReasonPhrase());
}
} catch (ClientProtocolException e) {
//TODO Handle problems..
} catch (IOException e) {
//TODO Handle problems..
}
return responseString;
}
@Override
protected void onPostExecute(String result) {
super.onPostExecute(result);
//Do anything with response..
}
}
我正在做一个 android 应用程序,我想从服务器 (http://10.0.2.2:8080/myserver/arquivo.txt) 读取一个文本文件并在我的应用程序中显示该文本。 我不知道该怎么做。 有人可以帮忙吗?
您可以使用此代码获取响应:
String textFileUrl = "http://10.0.2.2:8080/myserver/arquivo.txt"
String textFileText;
Request httpRequest = new Request();
httpRequest.execute(textFileUrl);
try {
textFileText = httpRequest.get(5000, TimeUnit.MILLISECONDS);
} catch (InterruptedException | ExecutionException | TimeoutException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
System.out.println("The online text file contains: " + textFileText);
TextView textView = (TextView)findViewById(R.id.textview);
textView.setText(textFileText);
创建一个名为 Request.java 的新文件:
import java.io.ByteArrayOutputStream;
import java.io.IOException;
import org.apache.http.HttpResponse;
import org.apache.http.HttpStatus;
import org.apache.http.StatusLine;
import org.apache.http.client.ClientProtocolException;
import org.apache.http.client.HttpClient;
import org.apache.http.client.methods.HttpGet;
import org.apache.http.impl.client.DefaultHttpClient;
import android.os.AsyncTask;
public class Request extends AsyncTask<String, String, String>{
HttpResponse response = null;
public Request(){
}
@Override
protected String doInBackground(String... uri) {
HttpClient httpclient = new DefaultHttpClient();
String responseString = null;
try {
response = httpclient.execute(new HttpGet(uri[0]));
StatusLine statusLine = response.getStatusLine();
if(statusLine.getStatusCode() == HttpStatus.SC_OK){
ByteArrayOutputStream out = new ByteArrayOutputStream();
response.getEntity().writeTo(out);
out.close();
responseString = out.toString();
} else{
//Closes the connection.
response.getEntity().getContent().close();
throw new IOException(statusLine.getReasonPhrase());
}
} catch (ClientProtocolException e) {
//TODO Handle problems..
} catch (IOException e) {
//TODO Handle problems..
}
return responseString;
}
@Override
protected void onPostExecute(String result) {
super.onPostExecute(result);
//Do anything with response..
}
}