选定的 Spinner Item 不会触发 onItemSelected - 方法

Question

我有一个设置片段，里面有 2 个微调器。我无法执行写入 onItemSelected 方法的代码。没有错误或异常。

我搜索了许多类似的问题，但 none 的解决方案对我有用。我不知道接下来要尝试什么。

public class SettingsFragment extends Fragment implements AdapterView.OnItemSelectedListener {

    @Override
    public View onCreateView(LayoutInflater inflater, ViewGroup container,
                             Bundle savedInstanceState) {

        //Getting the instance of Spinner and applying OnItemSelectedListener on it
        View view = inflater.inflate(R.layout.fragment_settings, container, false);

        Spinner spinnerBetrag = (Spinner) view.findViewById(R.id.spinnerBetrag);
        Spinner spinnerDetails = (Spinner) view.findViewById(R.id.spinnerDetails);

        spinnerBetrag.setOnItemSelectedListener(this);
        spinnerDetails.setOnItemSelectedListener(this);

        // Inflate the layout for this fragment
        return inflater.inflate(R.layout.fragment_settings, container, false);
    }


    @Override
    public void onItemSelected(AdapterView<?> parent, View view, int pos, long id) {
          //>>Problem: Code within this method is never beeing executed<<
    }

    @Override
    public void onNothingSelected(AdapterView<?> parent) {

    }

}

Answer 1

将 onCreateView 中的 return 语句更改为

return view;

您当前的 return 声明正在夸大一个全新的观点

Answer 2

将您的 onCreateView() 方法更改为 return view

@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container,
                         Bundle savedInstanceState) {

    //Getting the instance of Spinner and applying OnItemSelectedListener on it
    View view = inflater.inflate(R.layout.fragment_settings, container, false);

    Spinner spinnerBetrag = (Spinner) view.findViewById(R.id.spinnerBetrag);
    Spinner spinnerDetails = (Spinner) view.findViewById(R.id.spinnerDetails);

    spinnerBetrag.setOnItemSelectedListener(this);
    spinnerDetails.setOnItemSelectedListener(this);

    return view;  // add this instead
}

也为您的 onItemSelected() 添加

 public void onItemSelected(AdapterView<?> parent, View view, int pos, long id) {

     Spinner spinner = (Spinner) parent;
     if(spinner.getId() == R.id.spinnerBetrag)
     {
       Log.d("Spinner 1","selected");                 
     }
     else if(spinner.getId() == R.id.spinnerDetails)
     {
        Log.d("Spinner 2","selected");    
     }

}

选定的 Spinner Item 不会触发 onItemSelected - 方法

Selecting Spinner Item doesen't trigger onItemSelected - method

java

android

fragment

spinner

onitemselectedlistener