fps - 如何将计数除以时间函数以确定 fps

fps - how to divide count by time function to determine fps

我有一个计数器可以计算每一帧。我想做的是将其除以时间以确定我的程序的 FPS。但我不确定如何在 python.

内对计时函数执行操作

我试过将时间初始化为

fps_time = time.time 
fps_time = float(time.time)
fps_time = np.float(time.time)
fps_time = time()

然后计算fps,

FPS = (counter / fps_time)
FPS = float(counter / fps_time)
FPS = float(counter (fps_time))

但我得到的错误是对象不可调用或 / 的操作数不受支持:'int' 和 'buildin functions'

在此先感谢您的帮助!

你可能想做点这样的事:

def program():
  start_time = time.time() #record start time of program
  frame_counter = 0

  # random logic 
  for i in range(0, 100):
    for j in range(0, 100):
      # do stuff that renders a new frame
      frame_counter += 1 # count frame

  end_time = time.time() #record end time of program
  fps = frame_counter / float(end_time - start_time)

当然你不必等到程序结束才计算end_timefps,你可以时不时地在程序运行时报告 FPS。在报告当前 FPS 估计后重新启动 start_time 也有助于报告更精确的 FPS 估计。

  • 这是一种非常简单的方法,可以在每一帧打印程序的帧速率(不需要计数器):

    import time
    
    while True:
        start_time = time.time() # start time of the loop
    
        ########################
        # your fancy code here #
        ########################
    
        print("FPS: ", 1.0 / (time.time() - start_time)) # FPS = 1 / time to process loop
    
  • 如果你想要平均帧速率超过x秒,你可以这样做(需要计数器) :

    import time
    
    start_time = time.time()
    x = 1 # displays the frame rate every 1 second
    counter = 0
    while True:
    
        ########################
        # your fancy code here #
        ########################
    
        counter+=1
        if (time.time() - start_time) > x :
            print("FPS: ", counter / (time.time() - start_time))
            counter = 0
            start_time = time.time()
    

希望对您有所帮助!

很有魅力

import time
import collections

class FPS:
    def __init__(self,avarageof=50):
        self.frametimestamps = collections.deque(maxlen=avarageof)
    def __call__(self):
        self.frametimestamps.append(time.time())
        if(len(self.frametimestamps) > 1):
            return len(self.frametimestamps)/(self.frametimestamps[-1]-self.frametimestamps[0])
        else:
            return 0.0
fps = FPS()
for i in range(100):
    time.sleep(0.1)
    print(fps())

确保每帧调用一次 fps