MySQL 从中介算起 table

Question

我正在尝试在包含两个 ID 的中介 table 中找到最常用的类别，我运行这是为了查找类别中的所有帖子计数。

$data = $conn->query('SELECT * FROM category WHERE category_name ORDER BY category_name');

foreach($data as $row) {

$sql = "SELECT COUNT(p_id) FROM p_categories c,category ca WHERE c.category_id = ca.category_id AND category_name = :category_name";
$q = $conn->prepare($sql);
$q->execute(array(':category_name' => $row['category_name']));
$catco = $q->fetch();

echo '<p>'.$row['category_name'].' ('.$catco[0].')</p>';
}

这是 returns 所有类别，但我想将其限制为仅具有最多 p_id 的前四个类别。我尝试将计数查询限制为 4，但这没有用。

以下是 table：

帖子：p_id、p_name

p_categories: p_id, category_id

类别：category_id、category_name

Answer 1

您可以在单个查询中执行此操作

$sql = "SELECT p_categories.category_id, COUNT(*) AS cnt, category.category_name
        FROM p_categories 
        LEFT JOIN category
        ON p_categories.category_id = category.id 
        GROUP BY `category_id` 
        ORDER BY cnt 
        DESC LIMIT 4"

$data = $conn->query($sql); 
foreach($data as $row) {
    echo '<p>'.$row['category_name'].' ('.$row['cnt'] .')</p>';
}

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