反序列化 XML 到 C# XmlRoot 中的对象不起作用

Deserialize XML to object in C# XmlRoot is not working

我正在使用 asp.net (C#) 网站,我想 Deserialize XML 字符串使用 XmlSerializer class。

我的模型(.cs 文件)

[XmlRoot("MedicalClearanceFormRoot")]
  public class MedicalClearanceViewModel
  {


    [XmlAttribute("PassengerName")]
    public string PassengerName { get; set; }

    [XmlAttribute("Gender")]
    public string Gender { get; set; }

    [XmlAttribute("Age")]
    public string Age { get; set; }

    [XmlAttribute("PhoneNo")]
    public string PhoneNo { get; set; }

    [XmlAttribute("Email")]
    public string Email { get; set; }

    [XmlAttribute("BookingRefNo")]
    public string BookingRefNo { get; set; } 
}

XML 字符串

<MedicalClearanceFormRoot>
  <MedicalClearanceForm PassengerName="AAAAAAAAAAAAA" Age="11" PhoneNo="TTTTTTTTTTT" Email="ZZZZZZZZZZZZZZZZZZZ" BookingRefNo="11111111111111111111" />  
</MedicalClearanceFormRoot>

将XML反序列化为对象

的代码
string myXMLStringFromDB = GetXMLStringFromDb(); // this method will return XML from db.

    XmlSerializer serializer = new XmlSerializer(typeof(MedicalClearanceViewModel));
              using (TextReader reader = new StringReader(myXMLStringFromDB))
              {
               MedicalClearanceViewModel objModel = (MedicalClearanceViewModel)serializer.Deserialize(reader);
              }

但是,问题是当我使用上面的代码将 XML 反序列化为对象时...PassengerNameAgePhoneNo 等属性. 在 objModel

中仍然是空白

谁能帮我在 Class 上设置正确的 XML 符号 谁能帮我解决这个问题。

非常感谢任何帮助! 谢谢

要满足指定的 XML,我相信您需要这种 class 结构。

[XmlRoot("MedicalClearanceFormRoot")]
public class MedicalClearanceViewModel
{
    public MedicalClearanceFormElement MedicalClearanceForm { get; set; }
}

[XmlElement]
public class MedicalClearanceFormElement
{
    [XmlAttribute("PassengerName")]
    public string PassengerName { get; set; }

    [XmlAttribute("Gender")]
    public string Gender { get; set; }

    [XmlAttribute("Age")]
    public string Age { get; set; }

    [XmlAttribute("PhoneNo")]
    public string PhoneNo { get; set; }

    [XmlAttribute("Email")]
    public string Email { get; set; }

    [XmlAttribute("BookingRefNo")]
    public string BookingRefNo { get; set; } 
}

我已经创建了一个示例,代码将与下面完全一样。您的模型不正确。

 public class MedicalClearanceForm
{
    [XmlAttribute("PassengerName")]
    public string PassengerName { get; set; }

    [XmlAttribute("Gender")]
    public string Gender { get; set; }

    [XmlAttribute("Age")]
    public string Age { get; set; }

    [XmlAttribute("PhoneNo")]
    public string PhoneNo { get; set; }

    [XmlAttribute("Email")]
    public string Email { get; set; }

    [XmlAttribute("BookingRefNo")]
    public string BookingRefNo { get; set; }
}
[XmlRoot("MedicalClearanceFormRoot")]
public class MedicalClearanceFormRoot
{


    [XmlElement("MedicalClearanceForm")]
    public MedicalClearanceForm MedicalClearanceForm { get; set; }


}
class Program
{
    static void Main(string[] args)
    {
        string myXMLStringFromDB = @"<MedicalClearanceFormRoot><MedicalClearanceForm PassengerName = 'AAAAAAAAAAAAA' Age = '11' PhoneNo = 'TTTTTTTTTTT' Email = 'ZZZZZZZZZZZZZZZZZZZ' BookingRefNo = '11111111111111111111' /></MedicalClearanceFormRoot >";

        XmlSerializer serializer = new XmlSerializer(typeof(MedicalClearanceFormRoot));
        using (TextReader reader = new StringReader(myXMLStringFromDB))
        {
            MedicalClearanceFormRoot objModel = (MedicalClearanceFormRoot)serializer.Deserialize(reader);
        }

    }
}

您的 XML 的定义方式,您需要定义两个对象: - 一个用于 MedicalClearanceFormRoot xml 节点 - 一个用于 MedicalClearanceForm xml 节点

因此,您有两条路线可以选择:添加包装器 class 或更改您的 xml.

要添加包装器 class,您需要有一个 class 来表示 MedicalClearanceFormRoot,它有一个 属性 用于 MedicalClearanceForm 对象。然后将序列化器 class 更改为包装器 class。这是一个例子:

[XmlRoot("MedicalClearanceFormRoot")]
public class Wrapper
{
    public MedicalClearanceViewModel MedicalClearanceForm { get; set;}
}

public class MedicalClearanceViewModel
{

    [XmlAttribute("PassengerName")]
    public string PassengerName { get; set; }

    [XmlAttribute("Gender")]
    public string Gender { get; set; }

    [XmlAttribute("Age")]
    public string Age { get; set; }

    [XmlAttribute("PhoneNo")]
    public string PhoneNo { get; set; }

    [XmlAttribute("Email")]
    public string Email { get; set; }

    [XmlAttribute("BookingRefNo")]
    public string BookingRefNo { get; set; }
}


        XmlSerializer serializer = new XmlSerializer(typeof(Wrapper));
        using (TextReader reader = new StringReader(myXMLStringFromDB))
        {
            Wrapper objModel = (Wrapper)serializer.Deserialize(reader);
        }

选项 2:将您的 XML 更改为如下所示:

<MedicalClearanceFormRoot PassengerName="AAAAAAAAAAAAA" Age="11" PhoneNo="TTTTTTTTTTT" Email="ZZZZZZZZZZZZZZZZZZZ" BookingRefNo="11111111111111111111" >  
</MedicalClearanceFormRoot>