illustrator脚本，如果box1的值大于Box2，给出alert

Question

同一个脚本有 2 个不同的结果。当我写 4 位数字时。我收到这个错误。哪里可能不对。

var win = new Window('dialog', "Example");

win.size = [280,200];

var columns = win.add("group"); columns.spacing=5;

var width = columns.add('edittext {text: "", characters: 5, justify: "center"}');

var length = columns.add('edittext {text: "", characters: 5, justify: "center"}');

var height = columns.add('edittext {text: "", characters: 5, justify: "center"}');

width.active = true;


var grp = win.add('group');

var ok = grp.add('button {text: "OK"}')

grp.add('button {text: "Cancel"}');


var doBox = function(){

var box1=width.text;

var box2=length.text;

box1=width.text;

box2=length.text;

if (box1>box2)

   alert("You have entered a big number in the 1st box !");

else 

   alert("Ok");

}   

ok.onClick = doBox;

win.show();

Answer 1

请参阅this answer, for why this happens. to correct this problem you can use parseInt方法。为此，只需更改这些行

box1=width.text;
box2=length.text;

至

box1=parseInt(width.text);
box2=parseInt(length.text);

illustrator脚本，如果box1的值大于Box2，给出alert

illustrator script, If the value of box1 is greater than Box2, give alert

javascript

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