获取视图中多维数组的第一个和最后一个键
Getting the first and the last key of multi-dimensional arrays in views
我是 运行 函数并查询如下内容:
{
"Mar 22, 2015": [ ],
"Mar 23, 2015": [,
{
"id": 5,
"company_id": 1,
"task": "Do stuff right now",
"description": "Come on man! serious "
}
],
"Mar 24, 2015": [
{
"id": 8,
"company_id": 1,
"task": "Do all your taxes",
"description": "Or else you'll owe a bunch of money."
}
],
"Mar 25, 2015": [
{
"id": 2,
"company_id": 1,
"task": "Hey you",
"description": "Blah blah"
}
],
"Mar 26, 2015": [
{
"id": 1,
"company_id": 1,
"task": "Do something",
"description": "Oh ya!"
}
],
"Mar 27, 2015": [
{
"id": 4,
"company_id": 1,
"task": "Remember to do the laundry",
"description": "Oh la la!"
},
{
"id": 11,
"company_id": 1,
"task": "Buy a new snowboard",
"description": "blah blah"
},
{
"id": 12,
"company_id": 1,
"task": "Create your business plan",
"description": "blah blah"
}
],
"Mar 28, 2015": [ ]
}
我的数组将始终包含 7 天。我的问题是,我想获取第一个和最后一个日期(数组键)以在我的视图中输出(无需指定键值)。
自然想去{{ $myweek[0] }}
去Mar 22, 2015
,去{{ $myweek[6] }}
去Mar 28, 2015
。但我知道我不能用多维数组做到这一点。
如何将这些开始日期和结束日期添加到我的周数组中,而不必在日期中进行硬编码?
注意,我已经运行一个FOREACH
循环让这个变量显示每个日期.但我想获取 foreach 之外的值...以显示日期范围。 IE。 2015 年 3 月 22 日至 2015 年 3 月 28 日等的任务
希望您能理解以下代码的要点:
<?php
$arr = array(
'key1' => array(1,2,3),
'key2' => array(4,5,6),
'key3' => array(7,8,9),
'key4' => array(10,1,12),
'key5' => array(13,14,15),
);
$keys = array_keys($arr);
echo $keys[0] . ' AND ' . $keys[count($keys)-1];
更新:
如果你想在你的视图中这样做,那么你有两种方法:
1) 您需要将 $keys
传递给您的视图并从那里获取这些键。
2) 不传递键:($arr
是您传递给视图的变量)
{{ array_keys($arr)[0] }}
{{ array_keys($arr)[count($arr)-1] }}
使用array_keys:
<?php
$json = json_decode('{
"Mar 22, 2015": [ ],
"Mar 23, 2015": [
{
"id": 5,
"company_id": 1,
"task": "Do stuff right now",
"description": "Come on man! serious "
}
],
"Mar 24, 2015": [
{
"id": 8,
"company_id": 1,
"task": "Do all your taxes",
"description": "Or else you\'ll owe a bunch of money."
}
],
"Mar 25, 2015": [
{
"id": 2,
"company_id": 1,
"task": "Hey you",
"description": "Blah blah"
}
],
"Mar 26, 2015": [
{
"id": 1,
"company_id": 1,
"task": "Do something",
"description": "Oh ya!"
}
],
"Mar 27, 2015": [
{
"id": 4,
"company_id": 1,
"task": "Remember to do the laundry",
"description": "Oh la la!"
},
{
"id": 11,
"company_id": 1,
"task": "Buy a new snowboard",
"description": "blah blah"
},
{
"id": 12,
"company_id": 1,
"task": "Create your business plan",
"description": "blah blah"
}
],
"Mar 28, 2015": [ ]
}', true);
$keys = array_keys($json);
echo "From ".$keys[0]." to ".$keys[count($keys) - 1];
?>
我是 运行 函数并查询如下内容:
{
"Mar 22, 2015": [ ],
"Mar 23, 2015": [,
{
"id": 5,
"company_id": 1,
"task": "Do stuff right now",
"description": "Come on man! serious "
}
],
"Mar 24, 2015": [
{
"id": 8,
"company_id": 1,
"task": "Do all your taxes",
"description": "Or else you'll owe a bunch of money."
}
],
"Mar 25, 2015": [
{
"id": 2,
"company_id": 1,
"task": "Hey you",
"description": "Blah blah"
}
],
"Mar 26, 2015": [
{
"id": 1,
"company_id": 1,
"task": "Do something",
"description": "Oh ya!"
}
],
"Mar 27, 2015": [
{
"id": 4,
"company_id": 1,
"task": "Remember to do the laundry",
"description": "Oh la la!"
},
{
"id": 11,
"company_id": 1,
"task": "Buy a new snowboard",
"description": "blah blah"
},
{
"id": 12,
"company_id": 1,
"task": "Create your business plan",
"description": "blah blah"
}
],
"Mar 28, 2015": [ ]
}
我的数组将始终包含 7 天。我的问题是,我想获取第一个和最后一个日期(数组键)以在我的视图中输出(无需指定键值)。
自然想去{{ $myweek[0] }}
去Mar 22, 2015
,去{{ $myweek[6] }}
去Mar 28, 2015
。但我知道我不能用多维数组做到这一点。
如何将这些开始日期和结束日期添加到我的周数组中,而不必在日期中进行硬编码?
注意,我已经运行一个FOREACH
循环让这个变量显示每个日期.但我想获取 foreach 之外的值...以显示日期范围。 IE。 2015 年 3 月 22 日至 2015 年 3 月 28 日等的任务
希望您能理解以下代码的要点:
<?php
$arr = array(
'key1' => array(1,2,3),
'key2' => array(4,5,6),
'key3' => array(7,8,9),
'key4' => array(10,1,12),
'key5' => array(13,14,15),
);
$keys = array_keys($arr);
echo $keys[0] . ' AND ' . $keys[count($keys)-1];
更新: 如果你想在你的视图中这样做,那么你有两种方法:
1) 您需要将 $keys
传递给您的视图并从那里获取这些键。
2) 不传递键:($arr
是您传递给视图的变量)
{{ array_keys($arr)[0] }}
{{ array_keys($arr)[count($arr)-1] }}
使用array_keys:
<?php
$json = json_decode('{
"Mar 22, 2015": [ ],
"Mar 23, 2015": [
{
"id": 5,
"company_id": 1,
"task": "Do stuff right now",
"description": "Come on man! serious "
}
],
"Mar 24, 2015": [
{
"id": 8,
"company_id": 1,
"task": "Do all your taxes",
"description": "Or else you\'ll owe a bunch of money."
}
],
"Mar 25, 2015": [
{
"id": 2,
"company_id": 1,
"task": "Hey you",
"description": "Blah blah"
}
],
"Mar 26, 2015": [
{
"id": 1,
"company_id": 1,
"task": "Do something",
"description": "Oh ya!"
}
],
"Mar 27, 2015": [
{
"id": 4,
"company_id": 1,
"task": "Remember to do the laundry",
"description": "Oh la la!"
},
{
"id": 11,
"company_id": 1,
"task": "Buy a new snowboard",
"description": "blah blah"
},
{
"id": 12,
"company_id": 1,
"task": "Create your business plan",
"description": "blah blah"
}
],
"Mar 28, 2015": [ ]
}', true);
$keys = array_keys($json);
echo "From ".$keys[0]." to ".$keys[count($keys) - 1];
?>