如何在 Codeigniter 的多个环境检查中加载视图或使用 redirect()?
How to load view or use redirect() inside multiple environment check in Codeigniter?
想要检查环境,如果匹配某些情况,则想要重定向或加载某些视图。 get_instance();
无法在环境检查的 index.php 内部工作
我看起来像下面这样:
if (ENVIRONMENT === "production")
{
/*if(error ="db error")
redirect("/someview","refresh");
or load view header and footer
*/
}
i just confused about error handling mechanism in CI. By the help of Whosebug users i found steps to turn off the errors . but now i can't handle those errors.
如果你想处理某个错误,你可以将它重定向到流程中的某个视图,就像你在问题中提到的那样。
// Assuming you have a [Home] Controller that extends to your [Common] parent class
class Home extends Common {
public function index()
{
$this->load->helper('url');
$bCheck = false;
if ($bCheck !== true) {
$this->handleRedirectMethod('path/to/your/controller');
}
}
}
然后在你的父 [Common] 控制器上。 (例如 Common.php)
class Common extends CI_Controller
{
public function handleRedirectMethod($sUrl, $sMethodName = 'refresh', $sStatusCode = '302')
{
$sServerName = $_SERVER['REQUEST_SCHEME'] . '://' . $_SERVER['HTTP_HOST'];
redirect($sServerName . '/' . $sUrl, $sMethodName, $sStatusCode);
}
}
希望这能让您了解如何处理这些错误
想要检查环境,如果匹配某些情况,则想要重定向或加载某些视图。 get_instance();
无法在环境检查的 index.php 内部工作
我看起来像下面这样:
if (ENVIRONMENT === "production")
{
/*if(error ="db error")
redirect("/someview","refresh");
or load view header and footer
*/
}
i just confused about error handling mechanism in CI. By the help of Whosebug users i found steps to turn off the errors . but now i can't handle those errors.
如果你想处理某个错误,你可以将它重定向到流程中的某个视图,就像你在问题中提到的那样。
// Assuming you have a [Home] Controller that extends to your [Common] parent class
class Home extends Common {
public function index()
{
$this->load->helper('url');
$bCheck = false;
if ($bCheck !== true) {
$this->handleRedirectMethod('path/to/your/controller');
}
}
}
然后在你的父 [Common] 控制器上。 (例如 Common.php)
class Common extends CI_Controller
{
public function handleRedirectMethod($sUrl, $sMethodName = 'refresh', $sStatusCode = '302')
{
$sServerName = $_SERVER['REQUEST_SCHEME'] . '://' . $_SERVER['HTTP_HOST'];
redirect($sServerName . '/' . $sUrl, $sMethodName, $sStatusCode);
}
}
希望这能让您了解如何处理这些错误