unity 如何计算轮换玩家

Question

我想统一做一个保龄球游戏，我想在投球两次后改变球员，整个比赛持续4轮。所以我有两个球，每个球都有一个带有 playerController 的脚本，它可以围绕球移动，碰撞后它们会在原始位置重生。所以轮到我做了一个 gameController 启用 player1（球）输入并禁用 player2 输入然后它启用 player2 并禁用 player1。我怎样才能让玩家1玩两次然后换成玩家2.

脚本是：

public IEnumerator gamePlay()
{
    if (pl1.hasPlay == false)
    {            
        pl1.gameObject.SendMessage("Activate");
        pl2.gameObject.SendMessage("Deactivate");
    }

    if (pl1.hasPlay == true)
    {

        pl2.gameObject.SendMessage("Activate");
        pl1.gameObject.SendMessage("Deactivate");

    }
    yield return 0;
}

Answer 1

我建议使用两个整数：一个存储播放次数，另一个存储回合数。

看起来像这样：

private int plays;
private int rounds;

private void Start()
{
    plays = 0;
    rounds = 0;
    StartCoroutine(gamePlay());
}

public void NextBall()
{
    plays++;
    // Here you can change the logic behind the 2 balls
    // (I remember it changes depending on whether you did a strike or not, if it's your last play or not, ...)
    if (plays >= 2)
    {
        plays = 0;
        rounds++;
        StartCoroutine(gamePlay());
    }
}

public IEnumerator gamePlay()
{
    // This is based on player 1 being the first player
    pl1.hasPlay = (rounds % 2 == 0);
    pl2.hasPlay = !pl1.hasPlay;

    pl1.gameObject.SendMessage(pl1.hasPlay ? "Activate" : "Deactivate");
    pl2.gameObject.SendMessage(pl2.hasPlay ? "Activate" : "Deactivate");

    yield return 0;
}

我也不确定为什么你将 gamePlay() 声明为 IEnumerator 而不是作为一种方法，但我猜你需要这样:)

我把 if/else 条件改成了 ternary operator 因为两部分的内容相似，我觉得这样更容易阅读。

希望对您有所帮助，

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