使用 Swift 获取 iPhone 或 iPad 设备的 IP 地址 3

Question

如何使用Swift3编程语言在不使用任何第三方库的情况下检索设备的IP地址？我使用了以下代码来获取 IP 地址：

func getIPAddress() -> String? {
    var address : String?

    var ifaddr : UnsafeMutablePointer<ifaddrs> = nil
    if getifaddrs(&ifaddr) == 0 {

        var ptr = ifaddr
        while ptr != nil {
            defer { ptr = ptr.memory.ifa_next }

            let interface = ptr.memory

            let addrFamily = interface.ifa_addr.memory.sa_family
            if addrFamily == UInt8(AF_INET) || addrFamily == UInt8(AF_INET6) {

                if let name = String.fromCString(interface.ifa_name) where name == "en0" {

                    var hostname = [CChar](count: Int(NI_MAXHOST), repeatedValue: 0)
                    getnameinfo(interface.ifa_addr, socklen_t(interface.ifa_addr.memory.sa_len),
                                &hostname, socklen_t(hostname.count),
                                nil, socklen_t(0), NI_NUMERICHOST)
                    address = String.fromCString(hostname)
                }
            }
        }

        freeifaddrs(ifaddr)
    }

    return address
 }

但是 UnsafeMutablePointer<ifaddrs> 语法不起作用。它会引发语法错误。我需要导入一个框架来帮助我吗？

Answer 1

在桥接头中添加 #include<ifaddrs.h>。

这是获取 IP 地址所需的框架。

也可以参考以下link:

Answer 2

试试这个（不需要桥接头，它在 Playground 中有效）

//: Playground - noun: a place where people can play

import Darwin

var temp = [CChar](repeating: 0, count: 255)
enum SocketType: Int32 {
    case  SOCK_STREAM = 0, SOCK_DGRAM, SOCK_RAW
}

// host name
gethostname(&temp, temp.count)
// create addrinfo based on hints
// if host name is nil or "" we can connect on localhost
// if host name is specified ( like "computer.domain" ... "My-MacBook.local" )
// than localhost is not aviable.
// if port is 0, bind will assign some free port for us

var port: UInt16 = 0
let hosts = ["localhost", String(cString: temp)]
var hints = addrinfo()
hints.ai_flags = 0
hints.ai_family = PF_UNSPEC

for host in hosts {
    print("\n\(host)")
    print()

    // retrieve the info
    // getaddrinfo will allocate the memory, we are responsible to free it!
    var info: UnsafeMutablePointer<addrinfo>?
    defer {
        if info != nil
        {
            freeaddrinfo(info)
        }
    }
    var status: Int32 = getaddrinfo(host, String(port), nil, &info)
    guard status == 0 else {
        print(errno, String(cString: gai_strerror(errno)))
        continue
    }
    var p = info
    var i = 0
    var ipFamily = ""
    var ipType = ""
    while p != nil {
        i += 1
        // use local copy of info
        var _info = p!.pointee
        p = _info.ai_next

        switch _info.ai_family {
        case PF_INET:
            _info.ai_addr.withMemoryRebound(to: sockaddr_in.self, capacity: 1, { p in
                inet_ntop(AF_INET, &p.pointee.sin_addr, &temp, socklen_t(temp.count))
                ipFamily = "IPv4"
            })
        case PF_INET6:
            _info.ai_addr.withMemoryRebound(to: sockaddr_in6.self, capacity: 1, { p in
                inet_ntop(AF_INET6, &p.pointee.sin6_addr, &temp, socklen_t(temp.count))
                ipFamily = "IPv6"
            })
        default:
            continue
        }
        print(i,"\(ipFamily)\t\(String(cString: temp))", SocketType(rawValue: _info.ai_socktype)!)

    }

}

它打印在我的电脑上

localhost

1 IPv6  ::1 SOCK_RAW
2 IPv6  ::1 SOCK_DGRAM
3 IPv4  127.0.0.1 SOCK_RAW
4 IPv4  127.0.0.1 SOCK_DGRAM

Ivos-MacBook-Pro.local

1 IPv6  fe80::18a2:e892:fbd7:558e SOCK_RAW
2 IPv6  fe80::18a2:e892:fbd7:558e SOCK_DGRAM
3 IPv4  172.20.10.3 SOCK_RAW
4 IPv4  172.20.10.3 SOCK_DGRAM

Answer 3

为了获得设备的准确 IP 地址，我做了以下事情。由于我想包含更新的代码以使用 Swift 3 获取 IP 地址，因此我在此处发布了答案。引用自

在桥接头中添加 #include<ifaddrs.h>

创建以下函数以获取 IP 地址。

func getIP()-> String? {  

var address: String?
var ifaddr: UnsafeMutablePointer<ifaddrs>? = nil
if getifaddrs(&ifaddr) == 0 {

    var ptr = ifaddr
    while ptr != nil {
        defer { ptr = ptr?.pointee.ifa_next } // memory has been renamed to pointee in swift 3 so changed memory to pointee

        let interface = ptr?.pointee
        let addrFamily = interface?.ifa_addr.pointee.sa_family
        if addrFamily == UInt8(AF_INET) || addrFamily == UInt8(AF_INET6) {

            if let name: String = String(cString: (interface?.ifa_name)!), name == "en0" {  // String.fromCString() is deprecated in Swift 3. So use the following code inorder to get the exact IP Address.
                var hostname = [CChar](repeating: 0, count: Int(NI_MAXHOST))
                getnameinfo(interface?.ifa_addr, socklen_t((interface?.ifa_addr.pointee.sa_len)!), &hostname, socklen_t(hostname.count), nil, socklen_t(0), NI_NUMERICHOST)
                address = String(cString: hostname)
            }

        }
    }
    freeifaddrs(ifaddr)
  }

  return address
}

为了获取IP地址，print(getIP())

验证： -> 转到设置 -> Wi-Fi -> 单击 i 符号 -> 您可以检查您的设备 IP 地址。

输出屏幕截图：

使用 Swift 获取 iPhone 或 iPad 设备的 IP 地址 3

Get IPAddress of iPhone or iPad device Using Swift 3

iphone

ip-address

ipad

ios

swift3