TypeError: as_view() - Django

Question

我收到一个错误。

我不知道如何解决它，看看，这是错误：

TypeError: as_view() takes 1 positional argument but 2 were given

如您所见，这是我的 "model.py" 页面的代码。

from django.db import models
from django.contrib.gis.db import models


class RoadsLines(models.Model):
    gid = models.IntegerField()
    geom = models.MultiLineStringField()

    def __str__(self):              # __unicode__ on Python 2
        return '%s %s' % (self.gid, self.geom)

如您所见，这是我的 "views.py" 页面的代码。

from django.shortcuts import render
# Create your views here.
from django.shortcuts import render
from rest_framework import generics
from world.models import RoadsLines
from world.serializers import RoadsLinesSerializer


class ListCreateRoadsLines(generics.ListCreateAPIView):
    queryset = RoadsLines.objects.all()
    serializer_class = RoadsLinesSerializer

如您所见，这是我的 "urls.py" 页面的代码。

from django.conf.urls import url, include
from rest_framework import routers, serializers, viewsets
from world import views

# Routers provide an easy way of automatically determining the URL conf.
router = routers.DefaultRouter()
router.register(r'Roads', views.ListCreateRoadsLines)

# Wire up our API using automatic URL routing.
# Additionally, we include login URLs for the browsable API.
urlpatterns = [
    url(r'^', include(router.urls)),
    url(r'^api/', include('rest_framework.urls', namespace='rest_framework'))
]

我做错了什么？

提前致谢！

Answer 1

ListCreateRoadsLines 是视图，不是视图集。您应该将它包含在您的 url 模式中，而不是尝试注册它：

urlpatterns = [
    url(r'^Roads$', views.ListCreateRoadsLines.as_view()),
    url(r'^', include(router.urls)),
    url(r'^api/', include('rest_framework.urls', 
    namespace='rest_framework'))
]

TypeError: as_view() - Django

TypeError: as_view() - Django

python

django

web-services

geodjango

django-rest-framework