如何在plpgsql中使用变量内部函数

Question

我正在将来自触发器的值存储到 function.I 内的变量中，当我使用 function.Below 内的变量时出现错误是我的函数，触发器

CREATE OR REPLACE FUNCTION 
edm.automated_builder_update_trigger_manual()
RETURNS trigger AS
$BODY$
DECLARE
    e record;
    weekly_permit_table text := TG_ARGV[0];
BEGIN


Update  edm.weekly_permit_table as a
set applicant = applicant||' '||'-'||' '||new.builder where 
old.permit_number = split_part(a.permit_details, ' ',1);


RETURN NULL;
END;

还有我的触发器

CREATE TRIGGER builder_update_trigger_manual
 AFTER UPDATE
 ON edm.permit_table_manual_05_2017
 FOR EACH ROW
 WHEN (((old.builder)::text IS DISTINCT FROM (new.builder)::text))
 EXECUTE PROCEDURE 
edm.automated_builder_update_trigger_manual('weekly_permit_report_05_2017');

当我更新 'edm.permit_table_manual_05_2017' table 中的构建器值时，出现错误 'ERROR: relation edm.weekly_permit_table doesnot exist'

我知道这可能很愚蠢。但是我不确定我哪里错了。

Answer 1

CREATE OR REPLACE FUNCTION edm.automated_builder_update_trigger_manual()
RETURNS trigger AS
$BODY$
DECLARE
  e record;
  weekly_permit_table text := TG_ARGV[0];
BEGIN
  EXECUTE 
    format(
      $q$
        UPDATE edm.%I AS a SET
          applicant = concat(applicant,' - '||)
        WHERE 
           = split_part(a.permit_details, ' ',1)$q$,
      weekly_permit_table)
    USING NEW.builder, OLD.permit_number;
  RETURN NULL;
END $BODY$;

About EXECUTE

如何在plpgsql中使用变量内部函数

How to use variable inside function in plpgsql

sql

postgresql

triggers

plpgsql

postgresql-9.3