嵌套结构初始化
Nested Structure Initialization
#include<stdio.h>
#include<stdlib.h>
int main(){
struct nodeout
{
int out;
struct nodein{int in; };
};
struct nodeout* p;
p=(struct nodeout*)malloc(sizeof(struct nodeout));
p->out=10;
printf("%d",p->out);
}
..这是我的代码..我如何初始化结构nodein中的变量'in'?
您确实定义了 struct nodein
但没有为 struct nodeout
定义 nodein
成员。
进行如下操作:
#include<stdio.h>
#include<stdlib.h>
int main(){
struct nodeout
{
int out;
struct nodein {int in; } node_in;
};
struct nodeout* p;
p = (struct nodeout*)malloc(sizeof(struct nodeout));
p->out = 10;
p->node_in.in = 5
printf("%d %d”, p->out, p->node_in.in);
}
#include<stdio.h>
#include<stdlib.h>
int main(){
struct nodeout
{
int out;
struct nodein{int in; };
};
struct nodeout* p;
p=(struct nodeout*)malloc(sizeof(struct nodeout));
p->out=10;
printf("%d",p->out);
}
..这是我的代码..我如何初始化结构nodein中的变量'in'?
您确实定义了 struct nodein
但没有为 struct nodeout
定义 nodein
成员。
进行如下操作:
#include<stdio.h>
#include<stdlib.h>
int main(){
struct nodeout
{
int out;
struct nodein {int in; } node_in;
};
struct nodeout* p;
p = (struct nodeout*)malloc(sizeof(struct nodeout));
p->out = 10;
p->node_in.in = 5
printf("%d %d”, p->out, p->node_in.in);
}