Firebase

Question

我想从以下结构中枚举成员对象。我之前没有 node.js 方面的经验，我尝试了以下代码，但它似乎不起作用。

exports.sendVaultUnlockedPush = functions.database.ref('/Vaults/{id}/action').onUpdate(event => {
    let status = event.data.val();
    if (status == 'lock') {
        var db = admin.database();
        var vaultRef = db.ref("/Vaults/" + event.params.id);
        vaultRef.once('value').then(function(snapshot) {
            var hasMembers = snapshot.child('members');
            if (hasMembers) {
                var memberRef = db.ref("Vaults/" + event.params.id + "/members");
                memberRef.once('value').then(function(memberSnapshot) {
                    memberSnapshot.forEach(function(element) {
                        console(element.key + " - " + element.val());
                    }, this);
                });
            }
        });
    }
})

它抛出以下错误：

Error: Firebase.DataSnapshot.forEach failed: Was called with 2 arguments. Expects no more than 1. at Error (native) at z (/user_code/node_modules/firebase-admin/lib/database/database.js:42:1666) at T.forEach (/user_code/node_modules/firebase-admin/lib/database/database.js:114:179) at /user_code/index.js:34:36 at process._tickDomainCallback (internal/process/next_tick.js:135:7)

我只想 return 'members' 节点的值。而且我不知道做同样的事情。非常感谢您对此进行排序的任何帮助。谢谢！

Answer 1

根据docs forEach只需要一个参数：

这应该有效：

var values;
memberSnapshot.forEach(function(element) {
    console(element.key);
    values = element.val();
    for (var val in values) {
        if (values.hasOwnProperty(val)) {
            console(val, values[val]);
        }
    }
});

https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Statements/for...in

Firebase - 云功能：枚举 [Object Object]

Firebase - Cloud Functions: enumerate [Object Object]

node.js

firebase-realtime-database

google-cloud-functions