SQL 用于根据字符将单行数据拆分为多行

SQL for splitting a single row data into multiple rows based on character

到目前为止,我已经编写了一个将第一行拆分为多行的查询,但接下来 N 行的结果将是 N 行 returning 空值。

场景是这样的。

select address from sample;

这将 return 跟随 4 行,

Stack Overflow# is a# question and# answer site
Stack Overflow# is a# question and# answer site
Stack Overflow# is a# question and# answer site
Stack Overflow# is a# question and# answer site

当尝试使用以下查询将每一行拆分为多行时,

with test as (select address as str from sample)
select regexp_substr (str, '[^#]+', 1, rownum) split
from test
connect by level <= length (regexp_substr (str, '[^#]+', 1, rownum)) + 1
;

以下值将被 return编辑。

Stack Overflow
is a
question and
answer site
(null)
(null)
(null)

为什么我无法获得所有行的结果?

Why cant I get the results for all rows?

您的查询有两处不正确。

  1. 因为ROWNUM的使用不正确。您在同一查询中将 ROWNUM 用作条件,但是,ROWNUM 尚未递增到下一个值。所以,它的价值只有一个。所以,你只得到 1 行。

  2. 您需要对所有行进行拆分,而不仅仅是第一行。您需要遍历所有行。但是,同时你应该避免循环并摆脱重复。

有多种方法可以对多行​​进行字符串拆分。我已经在我的文章中展示了这里 http://lalitkumarb.wordpress.com/2015/03/04/split-comma-delimited-strings-in-a-table-using-oracle-sql/

例如,您可以这样做:

SQL> WITH t AS(
  2  SELECT 'Stack Overflow# is a# question and# answer site' text FROM dual UNION ALL
  3  SELECT 'Stack Overflow# IS a# question and# answer site' text FROM dual UNION ALL
  4  SELECT 'Stack Overflow# is a# question and# answer site' text FROM dual UNION ALL
  5  SELECT 'Stack Overflow# IS a# question and# answer site' text FROM dual
  6  )
  7  SELECT trim(regexp_substr(t.text, '[^#]+', 1, lines.column_value)) text
  8      FROM t,
  9        TABLE (CAST (MULTISET
 10        (SELECT LEVEL FROM dual CONNECT BY LEVEL <= regexp_count(t.text, '#')+1)
 11                     AS sys.odciNumberList
 12                    )
 13              ) lines
 14  /

TEXT
-----------------------------------------------
Stack Overflow
is a
question and
answer site
Stack Overflow
IS a
question and
answer site
Stack Overflow
is a
question and
answer site
Stack Overflow
IS a
question and
answer site

16 rows selected.

SQL>

因此,您现在得到 16 行。完美运行!