php 代码二响应未打印

Question

我已经尝试使用 post 请求从我的 table barrel_user 获取玩家 ID 的值我唯一的问题是两个响应不起作用但是如果我只给出一个它有效

        $customer_query="SELECT player_id FROM barrel_user where     phone_number='$phone_number'";
$fetchresult=mysqli_query($conn,$customer_query);

  if(mysqli_num_rows($fetchresult)>0)
{
  while($rows = mysqli_fetch_assoc($fetchresult)){

//  $response=$rows;


  if ($fetchresult) {
        $response["success"] = 1;
        //$response["player_id"]= $player_id;

            $player_id= $rows['player_id']; 
              $response=$rows;
    } else {
        $response["success"] = 0;
    }

  // $response["success"] = 'User Exists';
  }
}

以上是我的 php 代码，用于 post 请求

我没有得到这个值 $响应["success"] = 1;

但我得到的是 player_id

的值

注意：- 代码工作正常，如果我删除 $response=$rows 我会收到消息 success=1

Answer 1

试试这个

$response=array();
$customer_query="SELECT player_id FROM barrel_user where     phone_number='$phone_number'";
$fetchresult=mysqli_query($conn,$customer_query);

  if(mysqli_num_rows($fetchresult)>0)
{
  while($rows = mysqli_fetch_assoc($fetchresult)){

  if ($fetchresult) {
        $response["success"] = 1;
        //$response["player_id"]= $player_id;

            $player_id= $rows['player_id']; 
              $response[]=$player_id;
    } else {
        $response["success"] = 0;
    }

  }
}

php 代码二响应未打印

php code two response not printing

php

post

response