Bash确认输入或重新输入

Question

我有一个非常简单的 BASH 脚本，它询问用户是否愿意输入一些内容。响应是 y 或 n

如果他们输入 n 脚本将退出。

如果他们输入 y，那么他们会被问到一些问题。最后我想请他们确认输入。

如果正确我们将继续，如果不正确我想return他们到问题重新输入信息。

到目前为止我有：

while true; do
    echo -e "Enter details ? "
    read yn
    case $yn in
        [Nn]* ) exit;;
        [Yy]* ) 
            echo -e "description"
            read desc

            echo -e "Address"
            read address

        * ) echo "Please answer yes or no.";;
    esac
done

这似乎工作正常，所以我尝试添加确认.. 但那不起作用。

while true; do
    echo -e "Enter details ? "
    read yn
    case $yn in
        [Nn]* ) exit;;
        [Yy]* ) 
            echo -e "description"
            read desc

            echo -e "Address"
            read address

            echo -e "$desc - $address"

            while true; do
                echo -e "\nAre these details correct ? "
                read conf
                case $conf in
                    [Nn]* ) // return to enter details //
                    [Yy]* ) // carry on with the details entered // break;;
                esac
            done


        * ) echo "Please answer yes or no.";;
    esac
done

目的如下

用户选择y并输入描述和地址。该页面向他们显示了他们输入的内容的摘要，并询问他们 are these details correct ? 我们是否继续以及脚本是否继续。输入错误然后脚本 return 让他们输入描述，然后输入地址。

有人可以建议如何做到这一点。谢谢

Answer 1

您可以再添加一个循环级别并使用 break [n] 的可选级别指示器：

while true; do
    echo -e "Enter details ? "
    read yn
    case $yn in
        [Nn]*) exit;;
        [Yy]*)
            while true; do
                echo -e "description"
                read desc

                echo -e "Address"
                read address

                echo -e "$desc - $address"

                while true; do
                    echo -e "\nAre these details correct ? "
                    read conf
                    case $conf in
                        [Nn]* ) break 1;;
                        [Yy]* ) break 3;;
                    esac
                done
            done;;
        *) echo "Please answer yes or no.";;
    esac
done

Answer 2

不要为此使用 case。脚本示例：

#!/bin/bash

while true; do
    echo -e "Enter details ?(y/n)"
    read yn
    if [[ $yn == "y" ]];then
            echo -e "description"
            read desc

            echo -e "Address"
            read address

            echo -e "$desc - $address"

            while true; do
                echo -e "\nAre these details correct ? (y/n)"
                read conf
                if [[ $conf == "y" ]];then
                    echo "All done"
                    break
                elif [[ $conf == "n" ]];then
                    break
                else
                    continue
                fi
            done
    elif [[ $yn == "n" ]];then
        break
    else
        continue
    fi

Answer 3

好了：

DONE=""
while [ "$DONE" != "true" ]; do
    echo -e "Enter details ? "
    read yn
    case $yn in
        [Nn]* ) exit;;
        [Yy]* )
            echo -e "description"
            read desc

            echo -e "Address"
            read address

            echo -e "$desc - $address"

            while true; do
                echo -e "\nAre these details correct ? "
                read conf
                case $conf in
                    [Nn]* )
                        break;;
                    [Yy]* )
                        echo "doing something with your values"
                        DONE="true"
                        break;;
                esac
            done
        ;;


        * ) echo "Please answer yes or no.";;
    esac
done

Bash确认输入或重新输入

Bash confirm input or re enter

bash

prompt