Save Screenshot from ListView, Open Screenshot 不会打开最新版本

Save Screenshot from ListView, Open Screenshot does not opens the newest version

我尝试将整个ListView的截图保存为png格式保存在内存中并发送到其他应用程序。但如果我再做一次,截图就不是最新的了。一样的截图,不过我发之前改了数据

我使用以下代码创建屏幕截图:

  public static Bitmap getWholeListViewItemsToBitmap(SearchableAdapter adapter, ListView listview ) {
        int itemscount       = adapter.getCount();
        int allitemsheight   = 0;
        List<Bitmap> bmps    = new ArrayList<>();

        for (int i = 0; i < itemscount; i++) {

            View childView = adapter.getView(i, null, listview);
            childView.measure(View.MeasureSpec.makeMeasureSpec(listview.getWidth(), View.MeasureSpec.EXACTLY),
                    View.MeasureSpec.makeMeasureSpec(0, View.MeasureSpec.UNSPECIFIED));

            childView.layout(0, 0, childView.getMeasuredWidth(), childView.getMeasuredHeight());
            childView.setDrawingCacheEnabled(true);
            childView.destroyDrawingCache();
            childView.buildDrawingCache();
            bmps.add(childView.getDrawingCache());
            allitemsheight+=childView.getMeasuredHeight();
        }

        Bitmap bigbitmap    = Bitmap.createBitmap(listview.getMeasuredWidth(), allitemsheight, Bitmap.Config.ARGB_8888);
        Canvas bigcanvas    = new Canvas(bigbitmap);

        Paint paint = new Paint();
        int iHeight = 0;

        for (int i = 0; i < bmps.size(); i++) {
            Bitmap bmp = bmps.get(i);
            bigcanvas.drawBitmap(bmp, 0, iHeight, paint);
            iHeight+=bmp.getHeight();

            bmp.recycle();
            bmp=null;
        }
        return bigbitmap;
    }

此代码保存截图:

 public static boolean storeScreenshot(Context context, Bitmap screenshot) {
        try {
            File imagePath = new File(context.getCacheDir(), "images");
            if (!imagePath.exists())
                imagePath.mkdirs();
            File newFile = new File(imagePath, "image.png");
            if (newFile.exists()){
                newFile.delete();
                newFile = new File(imagePath, "image.png");
            }
            FileOutputStream stream = new FileOutputStream(newFile.getAbsolutePath()); // overwrites this image every time
            screenshot.compress(Bitmap.CompressFormat.PNG, 100, stream);
            stream.close();
            return true;
        } catch (IOException e) {
            e.printStackTrace();
            return false;
        }
    }

此代码打开屏幕截图并使用 shareintent 发送:

try {
    Helper.storeScreenshot(getApplicationContext(), Helper.getWholeListViewItemsToBitmap(adapter, listview));
    File imagePath = new File(getApplicationContext().getCacheDir(), "images");
    File screenshot = new File(imagePath, "image.png");
    Uri contentUri = null;
    if (screenshot.exists())
      contentUri = FileProvider.getUriForFile(getApplicationContext(), "com.myApp.fileprovider", screenshot);

    if (contentUri != null) {
      Intent shareIntent = new Intent();
      shareIntent.setAction(Intent.ACTION_SEND);

      shareIntent.addFlags(Intent.FLAG_GRANT_READ_URI_PERMISSION);
      shareIntent.setDataAndType(contentUri, getContentResolver().getType(contentUri));
      shareIntent.putExtra(Intent.EXTRA_STREAM, contentUri);

      startActivity(Intent.createChooser(shareIntent, "App auswählen"));
     }
 }
 catch(Exception e){
 Toast.makeText(getApplicationContext(),"Fehler beim Erstellen des Screenshots!", Toast.LENGTH_LONG);
 }

如果我尝试再次共享已更改数据的列表视图,它总是会发送一些旧的屏幕截图。

有人有想法吗?

非常感谢

解决方案是

"The cache isn't updated if the filename remains same. I solved this by deleting the contents of the directory and setting the filename to the current date in milliseconds. – Gurupad Mamadapur Apr 12 at 17:00"

所以我把save方法的代码改成了:

public static String storeScreenshot(Context context, Bitmap screenshot) {
        try {
            File imagePath = new File(context.getCacheDir(), "images");
            if (!imagePath.exists())
                imagePath.mkdirs();
            File[] imagePathDir = imagePath.listFiles();
            if(imagePathDir != null){
                for (File file : imagePathDir ){
                    file.delete();
                }
            }
            File screenshotFile = new File(imagePath, System.currentTimeMillis()+".png");
            FileOutputStream stream = new FileOutputStream(screenshotFile.getAbsolutePath());
            screenshot.compress(Bitmap.CompressFormat.PNG, 100, stream);
            stream.close();
            return screenshotFile.getName();
        } catch (IOException e) {
            e.printStackTrace();
            return "";
        }

是return文件名,现在可以了。