Hibernate 条件 MAX of SUM

Question

我怎样才能用标准 (JAVA)

实现这个 HQL

"SELECT MAX(pointsum) FROM (SELECT SUM(h.point) as pointsum FROM HealthPoint h WHERE h.player.partner = :partner GROUP BY h.player)"

我已经测试了这个但是我知道了但是我得到了属性 pointsum not found

DetachedCriteria detachedPlayer = DetachedCriteria.forClass(Player.class);
detachedPlayer.add(Restrictions.eq("partner", partner));
detachedPlayer.setProjection(Projections.property("id"));

Criteria criteria = getSessionFactory().getCurrentSession().createCriteria(HealthPoint.class);
criteria.add(Subqueries.propertyIn("player", detachedPlayer));
ProjectionList proj = Projections.projectionList();
proj.add(Projections.sum("point"));
proj.add(Projections.groupProperty("player"));
criteria.setProjection(Projections.alias(proj, "pointsum"));
criteria.setProjection(Projections.max("pointsum"));
return (Integer) criteria.uniqueResult();

提前致谢！

Answer 1

hql 不支持

在 hql 中可能无法使用 from 子句中的子查询。见 https://docs.jboss.org/hibernate/stable/core.old/reference/en/html/queryhql-subqueries.html

Note that HQL subqueries may occur only in the select or where clauses.

其他选项

我有两个建议来解决这个问题：排序和限制结果，或者创建一个视图。

将结果限制为您想要的结果：

.createQuery("SELECT SUM(h.point) as pointsum FROM HealthPoint h WHERE h.player.partner = :partner GROUP BY h.player order by pointsum desc")
.limit(1);

在数据库中创建一个视图，然后 select 从中创建

create view HealthPointSumsByPlayer 
as 
  select sum(point), player_id 
  from Health_Points 
  group by player_id;

然后 select（通过 hql）从那开始。

Hibernate 条件 MAX of SUM

Hibernate criteria MAX of SUM

java

hibernate

hql

criteria

hql 不支持

其他选项