如何在dataweave mule的过滤条件中传递动态字段名

Question

我在缓存中有数据，即对象库。我需要从缓存中获取数据并对其应用过滤条件。

这里的要求是，我必须公开 api 以获取基于 filedName 和 filedValue 的数据，这些数据将在请求中动态出现。

样品请求：

https://localhost:8082/api/customer/filter?fieldName=customerId&fieldValue=101810

我有 return 代码来过滤 dataweave 中的数据，但它不起作用。你能帮忙吗

%dw 1.0
%output application/json
---
payload.rows filter (("$.content." ++ flowVars.fieldName ++ ".content") as :string == flowVars.fieldValue as :string) map ((row , indexOfRow) -> {
    customerId: row.content.customerId.content as :string when row.content.customerId.content != null otherwise null,
    customerName: row.content.customerName.content as :string when row.content.customerName.content != null otherwise null,
    customerAddress:row.content.customerAddress.content as :string when row.content.customerAddress.content != null otherwise null
})

我遇到了以下错误

Exception while executing: 
payload.rows filter (("$.content." ++ flowVars.fieldName ++ ".content") as :string == flowVars.fieldValue as :string) map ((row , indexOfRow) -> {
                      ^
Type mismatch for '++' operator
     found :object, :string
  required :string, :string.

你能帮忙吗

Answer 1

问题出在用于选择器的代码上，它应该类似于 $.content[flowVars.fieldName].content。完整代码将是

%dw 1.0
%output application/json
---
payload.rows filter (($.content[flowVars.fieldName].content) as :string == flowVars.fieldValue as :string) map ((row , indexOfRow) -> {
    customerId: row.content.customerId.content as :string when row.content.customerId.content != null otherwise null,
    customerName: row.content.customerName.content as :string when row.content.customerName.content != null otherwise null,
    customerAddress:row.content.customerAddress.content as :string when row.content.customerAddress.content != null otherwise null
})

这与您提供的输入配合得很好。

希望对您有所帮助。