python 3 中如何对大数据进行RSA编码

Question

我尝试使用 pycrypto 库通过 python3.x 加密数据。它适用于短数据但不适用于长数组。如何加密长数据？我应该写一个包装器来将数据分割成更小的块吗？或者有没有其他可以处理长数据的加密库？

from Crypto.PublicKey import RSA
from Crypto import Random

random_generator = Random.new().read
key = RSA.generate(1024, random_generator)
publickey = key.publickey() 

"""
Shorter (128 bytes)
"""
msg = b'abcd'*32
print(msg)          # b'abcdabcdabcd...
enc=publickey.encrypt(msg, 32)
print(enc)          # Depends on key. Ex.: (b"hd\n\xbb\xe4\x8b...
dec=key.decrypt(enc)
print(dec)          # b'abcdabcdabcdabcda...

if msg==dec:        # TRUE
    print('TRUE')
else:
    print('FALSE')

"""
LONGER (132 bytes)
"""
msg = b'abcd'*33
print(msg)          # b'abcdabcdabcd...
enc=publickey.encrypt(msg, 32)
print(enc)          # Depends on key. Ex.: (b'\xa2J1;\xd4`\xc5i\x...   
dec=key.decrypt(enc)
print(dec)          # Depends on key. Ex.: b'|*\xb85\B\r2\xea\...   

if msg==dec:        # FALSE
    print('TRUE')
else:
    print('FALSE')

Answer 1

这不是原始问题的确切答案，但这解决了我的问题：基于 https://security.stackexchange.com/a/10953

... public-key cryptography is expensive for large messages; the public key algorithm is only used to encrypt the symmetric key and to sign a digest of the file.

所以不建议使用RSA加密大data/files。改为使用 AES：

from Crypto.Cipher import AES
obj = AES.new('This is a key123', AES.MODE_CBC, 'This is an IV456')
message = "The answer is no"*32
ciphertext = obj.encrypt(message)
print(ciphertext)
# '\xd6\x83\x8dd!VT\x92\xaa`A\x05\xe0\x9b\x8b\xf1'
obj2 = AES.new('This is a key123', AES.MODE_CBC, 'This is an IV456')
print(obj2.decrypt(ciphertext))
# 'The answer is no'

python 3 中如何对大数据进行RSA编码

How to RSA encode large data in python 3

large-files

pycrypto

python-3.x