从 txt 文件中删除第一行和 3 列

Question

我有一个格式如下的文件：

Received 4 packets, got 4 answers, remaining 252 packets
52:54:00:12:35:00 192.168.1.1
52:54:00:12:35:00 192.168.1.2
08:00:27:87:d3:08 192.168.1.3
08:00:27:3e:99:5c 192.168.1.23

我想删除第一行和所有行的 mac 列，输出应该是：

192.168.1.1
192.168.1.2
192.168.1.3
192.168.1.23

和后台命令运行我不需要在终端显示结果window

Answer 1

awk 'NR != 1 {print }' file1

在行动

$ cat file1
Received 4 packets, got 4 answers, remaining 252 packets
52:54:00:12:35:00 192.168.1.1
52:54:00:12:35:00 192.168.1.2
08:00:27:87:d3:08 192.168.1.3
08:00:27:3e:99:5c 192.168.1.23
$ awk 'NR != 1 {print }' file1
192.168.1.1
192.168.1.2
192.168.1.3
192.168.1.23

对于静默输出，您可以将输出定向到另一个文件。

$ awk 'NR != 1 {print }' file1 > file2
$ cat file2
192.168.1.1
192.168.1.2
192.168.1.3
192.168.1.23

从 txt 文件中删除第一行和 3 列

delete first line and 3 columns from txt file

linux

awk

hidden

cut

sed