python 抓取链接关键字

Question

我是 python 的新手，我需要帮助来抓取具有特定关键字的所有链接。问题是我收到以下错误：

if "air-max" in link["href"]: ^ IndentationError: expected an indented block.

这是我的代码

import requests
import time
from bs4 import BeautifulSoup

headers = {"Content-Type": "application/x-www-form-urlencoded; 
charset=UTF-8","X-Requested-With": "XMLHttpRequest","User-Agent": 
"Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.36 (KHTML, 
like Gecko) Chrome/56.0.2924.87 Safari/537.36"}

for i in range(0,4):   
url = "https://www.aw-lab.com/shop/uomo/scarpe?p={}".format(i)
r = requests.get(url)
soup = BeautifulSoup(r.content, "html.parser")

all_links = soup.find_all("a")
for link in all_links:
if link.has_key('href'):
if "air-max" in link["href"]:
    print(link["href"])

Answer 1

在 link.has_key('href'): 之后您需要另一个缩进级别。另外，要保持一致；始终使用空格（首选）或始终使用制表符。这可能并不总是正确的，但一般来说，如果行尾有一个 COLON :，那么下一行应该进一步缩进一级。

for i in range(0,4):   
    url = "https://www.aw-lab.com/shop/uomo/scarpe?p={}".format(i)
    r = requests.get(url)
    soup = BeautifulSoup(r.content, "html.parser")

    all_links = soup.find_all("a")
    for link in all_links:
        if link.has_key('href'):
            if "air-max" in link["href"]:
                print(link["href"])

Answer 2

请使用像 spyder IDE 或 jupyter notebook 这样的 IDE 进行开发。

import requests
import time
from bs4 import BeautifulSoup

headers = {"Content-Type": "application/x-www-form-urlencoded; 
charset=UTF-8","X-Requested-With": "XMLHttpRequest","User-Agent": 
"Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.36 (KHTML, 
like Gecko) Chrome/56.0.2924.87 Safari/537.36"}

for i in range(0,4):
    url = "https://www.aw-lab.com/shop/uomo/scarpe?p={}".format(i)
    r = requests.get(url)
    soup = BeautifulSoup(r.content, "html.parser")

all_links = soup.find_all("a")
for link in all_links:
    if link.has_key('href'):
        if "air-max" in link["href"]:
            print(link["href"])

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