Array.contains(其中:) 到 return return 为真的数组项

Question

在 Swift 中，假设我们有一个可拖动的 UIButton，它可以拖放到多个视图上。获取对所述视图的引用的最快方法是什么？

let Array: [UIViews] = [View1, View2, View3, View4, View5, View6]

func oneFingerSwipe(_ gesture:UIPanGestureRecognizer){
    let pointInView = gesture.location(in: gesture.view)

    switch(gesture.state){
            case .changed:
                Button.center = CGPoint(x: pointInView.x, y: pointInView.y)
            case .ended:
                if Array.contains(where: { [=12=].frame.contains(pointInView)}) {
                    // do something to said View([=12=]) through either Array[index] or reference to the View([=12=])
                }

//长篇大论

                if View1.frame.contains(pointInView) {
                    //do work to View1
                } else if View2.frame.contains(pointInView) {
                    //do work to View2
                } else if View3.frame.contains(pointInView) {
                    //do work to View3
                } else if View4.frame.contains(pointInView) {
                    //do work to View4
                } else if View5.frame.contains(pointInView) {
                    //do work to View5
                } else if View6.frame.contains(pointInView) {
                    //do work to View6
                }
            default: break
    }
}

Answer 1

您应该能够过滤视图数组并使用 first(where:) 函数获取第一个匹配的视图：

if let targetView = Array.first(where: {[=10=].frame.contains(pointInView)} ) {
    ...
}

Array.contains(其中:) 到 return return 为真的数组项

Array.contains(where:) to return Array item that returned true

arrays

contains

ios

swift