如何从结果集中生成嵌套数组结构？

Question

我有这个 Json 数组事件

[
    {
        "id": "4",
        "event_name": "Harliquins 7s",
        "event_description": "Ruggby game",
        "event_date": null,
        "event_venue": "UFA grounds",
        "event_company": "Harliquins",
        "event_image": "http://www.aal-europe.eu/wp-content/uploads/2013/12/events_medium.jpg",
        "event_ticket_no": "200",
        "paybill": "25666",
        "status": "0"
    },
    {
        "id": "5",
        "event_name": "christie &s",
        "event_description": "Ruggby",
        "event_date": "1-2-2917",
        "event_venue": "KISUMU ground",
        "event_company": "Kenya Games",
        "event_image": "N/A",
        "event_ticket_no": "400",
        "paybill": "79000",
        "status": "0"
    }
]

我也有这个选择

[
    {
        "id": "4",
        "event_id": "5",
        "options_id": "1",
        "seasonal": "1",
        "amount": "300"
    },
    {
        "id": "5",
        "event_id": "5",
        "options_id": "2",
        "seasonal": "1",
        "amount": "400"
    }
]

我想得到这个作为结果

[
    {
        "id": "4",
        "event_name": "Harliquins 7s",
        "event_description": "Ruggby game",
        "event_date": null,
        "event_venue": "UFA grounds",
        "event_company": "Harliquins",
        "event_image": "http://www.aal-europe.eu/wp-content/uploads/2013/12/events_medium.jpg",
        "event_ticket_no": "200",
        "paybill": "25666",
        "status": "0"
    },
    {
        "id": "5",
        "event_name": "christie &s",
        "event_description": "Ruggby",
        "event_date": "1-2-2917",
        "event_venue": "KISUMU ground",
        "event_company": "Kenya Games",
        "event_image": "N/A",
        "event_ticket_no": "400",
        "paybill": "79000",
        "status": "0",
        "Options:" [
            {
                 "id": "4",
                 "event_id": "5",
                 "options_id": "1",
                 "seasonal": "1",
                 "amount": "300"
             },
             {
                 "id": "5",
                 "event_id": "5",
                 "options_id": "2",
                 "seasonal": "1",
                 "amount": "400"
             }
         ]
    }
]

这是我的代码：

while( $row = $result->fetch_assoc()){
    $new_array[] =$row;
    $new_array['options'] =getTicketOptions($row['id']);
}
echo json_encode($new_array);

每个事件对象都有一个选项数组。

Answer 1

你快到了。您需要做的就是立即分配 $row 和 Options:

while( $row = $result->fetch_assoc()){
    $new_array[] = array($row, "Options" => getTicketOptions($row['id']));
}
echo json_encode($new_array);

原因是使用 $new_array[] 时您会自动设置一个新键而不知道它的值。因此，您以后不能轻易地向该记录中添加内容。两者同时进行即可为您解决。

Answer 2

在我看来你只需要合并 2 个对象：

$mergedObject = (object) array_merge((array) $events, (array) $options);

Answer 3

我想你想在最后一个位置添加第二个数组？？如果是，则按照答案进行操作。

第一个数组

[{"id":"4","event_name":"Harliquins 7s"},{"id":"5","event_name":"Harliquins 7s"}]

第二个数组

[{"id":"4","event_id":"5","options_id":"1"},{"id":"4","event_id":"5","options_id":"1"}]

需要数组

[{"id":"4","event_name":"Harliquins 7s"},{"id":"5","event_name":"Harliquins 7s","options":[{"id":"4","event_id":"5","options_id":"1"},{"id":"4","event_id":"5","options_id":"1"}]}]

Php代码

$last_key = end(array_keys($data));
        foreach ($data as $key => $value) {
            if($key == $last_key){
                $data[$key]['options'] = $data2;
            }

        }

        echo json_encode($data);

Answer 4

我使用 array_map and array_filter functions, You can try my code here: php sandbox 得到相同的结果，它总是在事件数组中创建选项属性：

$events = json_decode($events, true);
$options = json_decode($options, true);

$result = array_map( function ($item) use ($options) {

    $item['options'] = array_filter($options, function ($option) use ($item) {
       return $item['id'] == $option['event_id'];
    });

    return $item;

}, $events);

print_r($result);

如何从结果集中生成嵌套数组结构？

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