youtube preg_replace link 不同

Question

我将此代码制作成 preg_replace youtube 代码，但我遇到了问题，这是我的代码

// replace video Youtube to thumbnail       
$string     = array('http://youtube.com/watch?v=slBEtqC_JsI', 'https://youtu.be/bOxza0rLv1o');
//fix the '/' in the end of url
$string = trim($string, '/');
$search = array();
$search[0] = '~(?:https://(?:www\.)?youtube\.com\/watch\?v=)?([a-zA-Z0-9_\-+?:]+)~';
$search[1] = '~(?:https://(?:www\.)?youtu\.be\/)?([a-zA-Z0-9_\-+?:]+)~';
$replace = array();
$replace[1]    = 'https://i.ytimg.com/vi//hqdefault.jpg';   
$replace[0]   = 'https://i.ytimg.com/vi//hqdefault.jpg'; 
$soc_youtube = preg_replace($search,$replace,$string);

代码不改变字符串，输出将是

https://i.ytimg.com/vi/https:/hqdefault.jpg//https://i.ytimg.com/vi/i/hqdefault.jpg.https://i.ytimg.com/vi/ytimg/hqdefault.jpg.https://i.ytimg.com/vi/com/hqdefault.jpg/https://i.ytimg.com/vi/vi/hqdefault.jpg/https://i.ytimg.com/vi/https:/hqdefault.jpg/https://i.ytimg.com/vi/hqdefault/hqdefault.jpg.https://i.ytimg.com/vi/jpg/hqdefault.jpg//https://i.ytimg.com/vi/https:/hqdefault.jpg//https://i.ytimg.com/vi/i/hqdefault.jpg.https://i.ytimg.com/vi/ytimg/hqdefault.jpg.https://i.ytimg.com/vi/com/hqdefault.jpg/https://i.ytimg.com/vi/vi/hqdefault.jpg/https://i.ytimg.com/vi/youtu/hqdefault.jpg/https://i.ytimg.com/vi/hqdefault/hqdefault.jpg.https://i.ytimg.com/vi/jpg/hqdefault.jpg.https://i.ytimg.com/vi/https:/hqdefault.jpg//https://i.ytimg.com/vi/i/hqdefault.jpg.https://i.ytimg.com/vi/ytimg/hqdefault.jpg.https://i.ytimg.com/vi/com/hqdefault.jpg/https://i.ytimg.com/vi/vi/hqdefault.jpg/https://i.ytimg.com/vi/be/hqdefault.jpg/https://i.ytimg.com/vi/hqdefault/hqdefault.jpg.https://i.ytimg.com/vi/jpg/hqdefault.jpg/https://i.ytimg.com/vi/https:/hqdefault.jpg//https://i.ytimg.com/vi/i/hqdefault.jpg.https://i.ytimg.com/vi/ytimg/hqdefault.jpg.https://i.ytimg.com/vi/com/hqdefault.jpg/https://i.ytimg.com/vi/vi/hqdefault.jpg/https://i.ytimg.com/vi/bOxza0rLv1o/hqdefault.jpg/https://i.ytimg.com/vi/hqdefault/hqdefault.jpg.https://i.ytimg.com/vi/jpg/hqdefault.jpg);

有人可以帮我解决这个问题吗？感谢您的帮助

Answer 1

您可以使用

'~(?:https?://(?:www\.)?youtu(?:be\.com/watch\?v=|\.be/))?([a-zA-Z0-9_\-+?:]+)/?~'

见regex demo。图案详情：

(?: - 第一个交替组开始：
- https?://(?:www\.)?youtu - https:// 或 https://，然后是可选的 www. 子串，然后是 youtu 子串
- (?: - 第二个交替组开始：
  - be\.com/watch\?v= - be.com/watch?v= 子串
  - | - 或
  - \.be/ - .be/ 子字符串
- ) - 第二轮交替组结束
)? - 1 次或 0 次
([a-zA-Z0-9_\-+?:]+) - 第 1 组：一个或多个单词，-、+、? 或 : 个字符
/? - 一个可选的 /

参见 PHP demo online:

$string = array('http://youtube.com/watch?v=slBEtqC_JsI', 'https://youtu.be/bOxza0rLv1o', 'http://youtube.com/watch?v=slBEtqC_JSJ/');
$search = '~(?:https?://(?:www\.)?youtu(?:be\.com/watch\?v=|\.be/))?([a-zA-Z0-9_+?:-]+)/?~';
$replace = 'https://i.ytimg.com/vi//hqdefault.jpg';   
$soc_youtube = preg_replace($search,$replace,$string);
print_r($soc_youtube);

输出：

Array
(
    [0] => https://i.ytimg.com/vi/slBEtqC_JsI/hqdefault.jpg
    [1] => https://i.ytimg.com/vi/bOxza0rLv1o/hqdefault.jpg
    [2] => https://i.ytimg.com/vi/slBEtqC_JSJ/hqdefault.jpg
)

youtube preg_replace link 不同

youtube preg_replace link different

youtube

preg-replace