preg_match_all 来自其他站点的数据

preg_match_all data from other site

f.e 我们有这样的 tr,td 我想使用 preg_match_all 到 select 一些数据

<tr data-tag="tagid1" class="role-odd" role="row">
    <td class="sorting_1">pos</td>
    <td class="member_name" data-tag="tagid1">nick1</td>
    <td>rank1</td>
    <td>tagid2</td>
    <td class="right aligned">points</td>
    <td class="right aligned">lvl</td>
    <td data-sort="points">
        <img class="ui mini image" src="link" alt="desc">
    </td>
    <td class="right aligned" data-sort="points2">points2</td>
    <td class="right aligned" data-sort="points3">points3</td>
    <td>
        <div class="">
            <input id="compare-checkbox-tagid1" class="compareme" data-tag="tagid1" data-name="nick" type="checkbox">
        </div>
    </td>
</tr>
<tr data-tag="tagid2" class="role-even" role="row">
    <td class="sorting_1">pos</td>
    <td class="member_name" data-tag="tagid2">nick2</td>
    <td>rank2</td>
    <td>tagid2</td>
    <td class="right aligned">points</td>
    <td class="right aligned">lvl</td>
    <td data-sort="points">
        <img class="ui mini image" src="link">
    </td>
    <td class="right aligned" data-sort="points">points2</td>
    <td class="right aligned" data-sort="points3">points3</td>
    <td>
        <div class="">
            <input id="compare-checkbox-tagid2" class="compareme" data-tag="tagid2" data-name="nick" type="checkbox">
        </div>
    </td>
</tr>

如果我使用下面的代码

preg_match_all('#<tr[^>]+>(.+?)</tr>#ims',$out,$top);

$top 包含所有 trs,但我不需要所有数据,我想要以下数据:pos,nick,rank,tagid,points,lvl,points2,points3

谁能帮帮我?

您要获取 <td> 中的所有内容吗? 您可以尝试常规 #<td.*?>(.*)<\/td>#