如何在 C++ 中创建一个 class 是另一个 class 的向量？

Question

感谢阅读我的问题。

我正在尝试开始编写一个使用一副纸牌的程序，因为我想了解如何使用 classes。我决定创建一个 class 来存储西装和一个值，如下所示：

#ifndef CARD_H
#define CARD_H

class Card {        
    public:
        //here are the individual card values
        int _suit;
        int _value;
        Card(int suit, int value);
};

#endif

#include "card.h"

//define suits
const int spades = 0;
const int clubs = 1;
const int hearts = 2;
const int diamonds = 3;
//define face cards
const int jack = 11;
const int queen = 12;
const int king = 13;
const int ace = 14;

Card::Card(int suit, int value){
    _suit = suit;
    _value = value;
}

然后我决定创建一副牌组 class，并在其中 class 通过分配 0-3（花色）的值然后分配 2-14（排名）的值来初始化我的卡片卡）。我还将卡片添加到我定义的用于保存它们的向量中，如下所示：

#ifndef DECK_H
#define DECK_H

#include <vector>

class Deck {
    public:
        std::vector<Card> _deck(51);
        Deck();
};

#endif

#include <iostream>
#include <vector>

#include "card.h"
#include "deck.h"

const int all_suits = 4 - 1;
const int all_values = 14;

Deck::Deck(){
    int i = 0;
    for (int j = 0; j <= all_suits; ++j) {
        //begin with 2 because card can't have value 0
        for (int k = 2; k <= all_values; ++k) {
            _deck[i] = Card(j, k);
            ++i;
        }
    }
}

当我尝试像这样测试程序时，这不知何故给我带来了问题：

#include <iostream>
#include <vector>

#include "card.h"
#include "deck.h"

int main() {
    Deck new_deck = Deck();
    std::cout << new_deck._deck[4]._value;
  return 0;
}

当我尝试运行代码时出现以下错误：

In file included from main.cpp:6:
./deck.h:8:27: error: expected parameter declarator
                std::vector<Card> _deck(51);
                                        ^
./deck.h:8:27: error: expected ')'
./deck.h:8:26: note: to match this '('
                std::vector<Card> _deck(51);
                                       ^
main.cpp:22:24: error: reference to non-static member function must be called; did you mean to call it with no arguments?
        std::cout << new_deck._deck[4]._value;
                     ~~~~~~~~~^~~~~
                                   ()
3 errors generated.
In file included from deck.cpp:8:
./deck.h:8:27: error: expected parameter declarator
                std::vector<Card> _deck(51);
                                        ^
./deck.h:8:27: error: expected ')'
./deck.h:8:26: note: to match this '('
                std::vector<Card> _deck(51);
                                       ^
deck.cpp:18:4: error: reference to non-static member function must be called; did you mean to call it with no arguments?
                        _deck[i] = Card(j, k);
                        ^~~~~
                             ()
3 errors generated.

老实说，我不太确定发生了什么。我非常关注我在网上看到的一个 classes 的例子。如果有人可以帮助我找到问题所在，将不胜感激。对不起，我对此有点陌生，可能犯了一些愚蠢的错误。非常感谢您花时间和耐心阅读本文并帮助我。

Answer 1

你的问题在于_deck的声明：

class Deck {
    public:
        std::vector<Card> _deck(51);

在这里您试图声明 _deck 并调用构造函数，但您不能从 class 成员初始化程序中这样做。可以为没有构造函数的数据成员执行此操作，例如：

class Deck {
    public:
        int no_of_cards = 51;
        std::vector<Card> _deck;

您将需要使用构造函数来初始化 _deck（就像您已经在做的那样：

Deck::Deck() {
    _deck.reserve(51);
    int i = 0;
    for (int j = 0; j <= all_suits; ++j) {
        //begin with 2 because card can't have value 0
        for (int k = 2; k <= all_values; ++k) {
            _deck.push_back(Card(j, k));
            ++i;
        }
    }
}

并将您对 _deck 的声明保留为：

class Deck {
    public:
        std::vector<Card> _deck;

如何在 C++ 中创建一个 class 是另一个 class 的向量？

How can I create a class that is a vector of another class in C++?

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