Matplotlib 中的可拖动线 select

Question

我正在尝试使用 matplotlib 处理和拾取创建 class 可拖动线。目的是在图形上设置不同的阈值和间隔。这是代码：

import matplotlib.pyplot as plt
import matplotlib.lines as lines
import numpy as np

class draggable_lines:

    def __init__(self, ax, kind, XorY):

        self.ax = ax
        self.c = ax.get_figure().canvas
        self.o = kind
        self.XorY = XorY

        if kind == "h":
            x = [-1, 1]
            y = [XorY, XorY]

        elif kind == "v":
            x = [XorY, XorY]
            y = [-1, 1]

        else:
            print("choose h or v line")

        self.line = lines.Line2D(x, y, picker=5)
        self.ax.add_line(self.line)
        self.c.draw()
        sid = self.c.mpl_connect('pick_event', self.clickonline)

    # pick line when I select it 
    def clickonline(self, event):

        self.active_line = event.artist
        print("line selected ", event.artist)
        self.follower = self.c.mpl_connect("motion_notify_event", self.followmouse)
        self.releaser = self.c.mpl_connect("button_press_event", self.releaseonclick)

    # The selected line must follow the mouse
    def followmouse(self, event):

        if self.o == "h":
            self.line.set_ydata([event.ydata, event.ydata])
        else:
            self.line.set_xdata([event.xdata, event.xdata])

        self.c.draw()

    # release line on click
    def releaseonclick(self, event):

        if self.o == "h":
            self.XorY = self.line.get_ydata()[0]
        else:
            self.XorY = self.line.get_xdata()[0]

        print (self.XorY)

        self.c.mpl_disconnect(self.releaser)
        self.c.mpl_disconnect(self.follower)


plt.ion()
fig = plt.figure()
ax = fig.add_subplot(111)
Vline = draggable_lines(ax, "h", 0.5)
Tline = draggable_lines(ax, "v", 0.5)
Tline2 = draggable_lines(ax, "v", 0.1)

该行为是我仅使用 1 行时的预期行为（即使它在我释放该行时也会通知 selection）。

当我使用多条线路时，它 select 会同时使用所有线路！

我想我误解了事件管理器的功能，但我不明白为什么不同的对象，很好区分（正如我在 print("line selected ", event.artist) 中看到的）应该 select 自己和另一个！

Answer 1

有人可能会问不同的问题：如果你点击其中任何一条线，matplotlib 如何知道要拖动哪条线？答：不会，因为它有3个回调，每行一个，会全部执行。

因此，解决方案是首先检查单击的行是否实际上是要在 'pick_event' 回调中移动的行：

if event.artist == self.line:
    # register other callbacks

（换句话说：如果不经常调用 canvas.draw()，而是调用 canvas.draw_idle()，您会受益匪浅）

import matplotlib.pyplot as plt
import matplotlib.lines as lines

class draggable_lines:
    def __init__(self, ax, kind, XorY):
        self.ax = ax
        self.c = ax.get_figure().canvas
        self.o = kind
        self.XorY = XorY

        if kind == "h":
            x = [-1, 1]
            y = [XorY, XorY]

        elif kind == "v":
            x = [XorY, XorY]
            y = [-1, 1]
        self.line = lines.Line2D(x, y, picker=5)
        self.ax.add_line(self.line)
        self.c.draw_idle()
        self.sid = self.c.mpl_connect('pick_event', self.clickonline)

    def clickonline(self, event):
        if event.artist == self.line:
            print("line selected ", event.artist)
            self.follower = self.c.mpl_connect("motion_notify_event", self.followmouse)
            self.releaser = self.c.mpl_connect("button_press_event", self.releaseonclick)

    def followmouse(self, event):
        if self.o == "h":
            self.line.set_ydata([event.ydata, event.ydata])
        else:
            self.line.set_xdata([event.xdata, event.xdata])
        self.c.draw_idle()

    def releaseonclick(self, event):
        if self.o == "h":
            self.XorY = self.line.get_ydata()[0]
        else:
            self.XorY = self.line.get_xdata()[0]

        print (self.XorY)

        self.c.mpl_disconnect(self.releaser)
        self.c.mpl_disconnect(self.follower)

fig = plt.figure()
ax = fig.add_subplot(111)
Vline = draggable_lines(ax, "h", 0.5)
Tline = draggable_lines(ax, "v", 0.5)
Tline2 = draggable_lines(ax, "v", 0.1)
plt.show()

Matplotlib 中的可拖动线 select

Draggable lines select one another in Matplotlib

python

lines

matplotlib

event-handling

drag