Scrapy Request - 处理一组又一组的 url - 我可以使用优先级吗?

Scrapy Request - process one group of urls after another - can I use priority?

如何使 scrapy 处理一个 group/list 个 url?我有两个网址列表。我必须处理第一个列表,包括 item pipelines,然后我可以处理第二个列表。

两者都应该由一个蜘蛛处理。

我不确定 priority 是否对我有帮助。

priority (int) – the priority of this request (defaults to 0). The priority is used by the scheduler to define the order used to process requests. Requests with a higher priority value will execute earlier. Negative values are allowed in order to indicate relatively low-priority.

因为我不知道它是否只是根据优先级重新排序 Requests - 它可能会在第一个列表的最后一个 url 之前通过 pipelinenig 来自第二个列表的第一个 url 结束。

我能否确定第一个列表中的 items 会先于第二个列表中的导出到 XML(我正在使用 XMLItemExporter)?

编辑:

错误(@Wilfredo):

2017-11-23 20:12:16 [scrapy.utils.signal] ERROR: Error caught on signal handler: > Traceback (most recent call last): File "/home/milano/.virtualenvs/eoilenv/local/lib/python2.7/site-packages/scrapy/utils/signal.py", line 30, in send_catch_log *arguments, **named) File "/home/milano/.virtualenvs/eoilenv/local/lib/python2.7/site-packages/pydispatch/robustapply.py", line 55, in robustApply return receiver(*arguments, **named) TypeError: spider_idle() takes exactly 2 arguments (1 given) 2017-11-23 20:12:16 [scrapy.core.engine] INFO: Closing spider (finished)

编辑二:

# coding=utf-8
import scrapy
from bot.items import TestItem
from scrapy import Spider, Request, signals
from scrapy.exceptions import DontCloseSpider


class IndexSpider(Spider):
    name = 'index_spider'
    allowed_domains = ['www.scrape.com']

    def start_requests(self):
        for url in ["https://www.scrape.com/eshop"]:
            # for url in ["https://www.scrape.com/search/getAjaxResult?categoryId=1&"]:
            yield Request(url, callback=self.parse_main_page)

    def parse_main_page(self, response):
        # get subcategories and categories
        self.categories = []
        self.subcategories = []
        parts = response.selector.xpath("//div[contains(@class,'side-nav') and not(contains(@class,'side-nav-'))]")

        for part in parts:
            part_name = part.xpath('.//h4/text()').extract_first().strip()
            category_list = [part_name]
            categories_ul = part.xpath('./ul')
            categories_lis = categories_ul.xpath('./li')
            for category_li in categories_lis:
                category_list = category_list[:1]
                category_name = category_li.xpath('./a/text()').extract_first().strip()
                category_href = category_li.xpath('./a/@href').extract_first().strip()
                categoryId = self._extract_categoryId_from_url(category_href)
                category_list.append(category_name)
                self.categories.append((categoryId, category_list))
                subcategories_lis = category_li.xpath('.//li')

                for subcategory_li in subcategories_lis:
                    category_list = category_list[:2]
                    subcategory_href = subcategory_li.xpath('./a/@href').extract_first()
                    subcategory_name = subcategory_li.xpath('./a/text()').extract_first().strip()
                    subcategoryId = self._extract_categoryId_from_url(subcategory_href)
                    category_list.append(subcategory_name)
                    self.subcategories.append((subcategoryId, category_list))
        # Scrape all subcategories (then categories)

        # for sub in self.subcategories:
        #     url = "https://www.scrape.com/search/getAjaxResult?categoryId={}".format(sub[0])
        #     yield Request(url,meta={'tup':sub,'priority':1,'type':'subcategory'},priority=1,callback=self.parse_category)


    def parse_category(self, response):
        tup = response.meta['tup']
        type = response.meta['type']
        priority = response.meta['priority']
        current_page = response.meta.get('page', 1)
        categoryId = tup[0]
        categories_list = tup[1]
        number_of_pages_href = response.selector.xpath(u'//a[text()="Last"]/@href').extract_first()
        try:
            number_of_pages = int(number_of_pages_href.split('p=')[1].split('&')[0])
        except:
            number_of_pages = current_page
        if current_page < number_of_pages:
            url = "https://www.scrape.com/search/getAjaxResult/?categoryId={}&p={}".format(categoryId, current_page + 1)
            yield Request(url, self.parse_category, meta={'tup': tup, 'page': current_page + 1,'priority':priority,'type':type}, priority=priority)
        hrefs = self._extract_all_product_urls(response)
        for href in hrefs:
            yield Request(href, self.parse_product, meta={"categories_list": categories_list,'type':type}, priority=2 if priority==1 else -1)

    def parse_product(self, response):
        yield TestItem(url=response.url,type=response.meta['type'], category_text='|'.join(response.meta['categories_list']))

    def _extract_categoryId_from_url(self, url):
        categoryId = url.split('/')[-2]
        return categoryId

    def _extract_all_product_urls(self, response):
        hrefs = response.selector.xpath("//a[contains(@class, 'shop-item-image')]/@href").extract()
        return [u"https://www.scrape.com{}".format(x) for x in hrefs]

    @classmethod
    def from_crawler(cls, crawler, *args, **kwargs):
        spider = super(IndexSpider, cls).from_crawler(crawler, *args, **kwargs)
        crawler.signals.connect(spider.spider_idle,
                                signal=scrapy.signals.spider_idle)
        return spider

    def spider_idle(self):
        self.crawler.signals.disconnect(self.spider_idle,
                                        signal=scrapy.signals.spider_idle)
        # yield a new group of urls
        if self.categories:
            for cat in self.categories:
                url = "https://www.scrape.com/search/getAjaxResult?categoryId={}".format(cat[0])
                yield Request(url, meta={'tup': cat, 'priority': 0, 'type': 'category'}, priority=0,
                              callback=self.parse_category)
            self.categories = []
            raise DontCloseSpider()

为了确保一个请求接踵而至,我会这样做:

def start_requests(self):
    urls = ['url1', 'url2']
    yield Request(
        url=urls[0], 
        callback=self.process_request, 
        meta={'urls': urls, 'current_index':0}

def process_request(self, response):
    # do my thing
    yield {} # yield item
    current_index = response.meta['current_index'] + 1
    if current_index < len(response.meta['urls']:
        yield Request(
            url=response.meta['urls'][current_index], 
            callback=self.process_request, 
            meta={'urls': response.meta['urls'], 'current_index': current_index})

是的,优先级 url(具有更高优先级的请求)首先由调度程序处理,以确保您可以设置较低的并发性 CONCURRENT_REQUESTS = 1 原因是如果您使用更大的并发一些低优先级 urls 可能在您排队一些新请求时已经下载,这可能会给您留下不遵守顺序的印象。

另一种选择(如果您需要更高的并发性)是定义 a spider_idle method (my bad, thanks to @eLRuLL for pointing this up) and yield the requests from the second group, yielding also a DontCloseSpider 异常,如下所示:

# -*- coding: utf-8 -*-
import scrapy
from scrapy.exceptions import DontCloseSpider

class ExampleSpider(scrapy.Spider):
    name = 'example'
    allowed_domains = ['example.com']

    first_group_of_urls = [
        'http://quotes.toscrape.com/page/1/'
    ]
    second_group_of_urls = [
        'http://quotes.toscrape.com/page/2/'
    ]

    def start_requests(self):
        for url in self.first_group_of_urls:
            yield scrapy.Request(url=url, callback=self.parse)

    def parse(self, response):
        self.logger.debug('In response from %s', response.url)

    @classmethod
    def from_crawler(cls, crawler, *args, **kwargs):
        spider = super(ExampleSpider, cls).from_crawler(crawler, *args, **kwargs)
        crawler.signals.connect(spider.spider_idle,
                                signal=scrapy.signals.spider_idle)
        return spider

    def spider_idle(self):
        self.crawler.signals.disconnect(self.spider_idle,
                                        signal=scrapy.signals.spider_idle)
        for url in self.second_group_of_urls:
            self.crawler.engine.crawl(scrapy.Request(url), self)
        raise DontCloseSpider