将 Dataframe 列转换为 python 中的时间格式
Convert Dataframe column to time format in python
我有一个数据框列,如下所示:
显示为M:S.MS
。如何将其转换为 M:S:MS timeformat
以便将其绘制为时间序列图?
如果我按原样绘制,python 会抛出 Invalid literal for float()
错误。
Note
: This dataframe contains one hour worth of data. Values between
0:0.0 - 59:59.9
df = pd.DataFrame({'date':['00:02.0','00:05:0','00:08.1']})
print (df)
date
0 00:02.0
1 00:05:0
2 00:08.1
可以转换为datetime
:
df['date'] = pd.to_datetime(df['date'], format='%M:%S.%f')
print (df)
date
0 1900-01-01 00:00:02.000
1 1900-01-01 00:00:05.000
2 1900-01-01 00:00:08.100
或 timedelta
s:
df['date'] = pd.to_timedelta(df['date'].radd('00:'))
print (df)
date
0 00:00:02
1 00:00:05
2 00:00:08.100000
编辑:
自定义日期使用:
date = '2015-01-04'
td = pd.to_datetime(date) - pd.to_datetime('1900-01-01')
df['date'] = pd.to_datetime(df['date'], format='%M:%S.%f') + td
print (df)
date
0 2015-01-04 00:00:02.000
1 2015-01-04 00:00:05.000
2 2015-01-04 00:00:08.100
我有一个数据框列,如下所示:
显示为M:S.MS
。如何将其转换为 M:S:MS timeformat
以便将其绘制为时间序列图?
如果我按原样绘制,python 会抛出 Invalid literal for float()
错误。
Note : This dataframe contains one hour worth of data.
Values between 0:0.0 - 59:59.9
df = pd.DataFrame({'date':['00:02.0','00:05:0','00:08.1']})
print (df)
date
0 00:02.0
1 00:05:0
2 00:08.1
可以转换为datetime
:
df['date'] = pd.to_datetime(df['date'], format='%M:%S.%f')
print (df)
date
0 1900-01-01 00:00:02.000
1 1900-01-01 00:00:05.000
2 1900-01-01 00:00:08.100
或 timedelta
s:
df['date'] = pd.to_timedelta(df['date'].radd('00:'))
print (df)
date
0 00:00:02
1 00:00:05
2 00:00:08.100000
编辑:
自定义日期使用:
date = '2015-01-04'
td = pd.to_datetime(date) - pd.to_datetime('1900-01-01')
df['date'] = pd.to_datetime(df['date'], format='%M:%S.%f') + td
print (df)
date
0 2015-01-04 00:00:02.000
1 2015-01-04 00:00:05.000
2 2015-01-04 00:00:08.100