MYSQl

Question

我是 MYSQL 的新手，在 group_concat 语句中需要一些帮助。我有以下 table

Seller Merchant CustomerID
S1     M1       C1
S1     M1       C1
S1     M1       C2
S1     M1       C3
S1     M1       C4
S2     M2       C5
S2     M2       C6
S3     M3       C6

对于同一卖家和商家的组合，所有具有不同customerID的商品及其重复次数。

我可以使用 group_concat 推导出唯一客户 IDS 的数量，但无法获得该数量。

SELECT * , LENGTH(CUSTIDS) - LENGTH(REPLACE(CUSTIDS,',',''))+1 AS COUNT_OF_CUSTIDS
FROM (SELECT SELLER, MERCHANT, GROUP_CONCAT(CUSTOMERID SEPARATOR '|') AS CUSTIDS
FROM TABLE
GROUP BY SELLER, MERCHANT
HAVING COUNT(DISTINCT CUSTOMERID ) >1 
)

这给了我下面的结果

Seller Merchant CustomerID    COUNT_OF_CUSTIDS
S1     M1       C1,C2,C3,C4   4
S2     M2       C5,C6         2

而我想要下面的

Seller Merchant CustomerID                 COUNT_OF_CUSTIDS
S1     M1       C1(2),C2(1),C3(1),C4(1)    4
S2     M2       C5(1),C6(1)                2

Answer 1

您需要先在 seller/merchant/customerid 级别进行聚合以获得计数。然后你可以继续你的聚合：

  SELECT SELLER, MERCHANT,
         COUNT(*) as COUNT_OF_CUSTIDS,
         GROUP_CONCAT(CUSTOMERID, ' (', cnt, ')' SEPARATOR '|') AS CUSTIDS
  FROM (SELECT SELLER, MERCHANT, COUNT(*) as cnt
        FROM TABLE
        GROUP BY SELLER, MERCHANT, CUSTOMERID
       ) t
  GROUP BY SELLER, MERCHANT
  HAVING COUNT(* ) > 1

MYSQl - Group_Concat 内的元素数

MYSQl - Count of elements inside Group_Concat

sql

group-concat